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dalvyx [7]
2 years ago
6

8(1/4x + 12 - 1/2x) = 82

Mathematics
2 answers:
Andrew [12]2 years ago
8 0

Answer:

x=7

Step-by-step explanation:

8(1X/4 +12 - 1 x 1/2X)=82

8(X/4 +12-1 x 1/2 x X)=82

8(X/4+ 12 - 1/2x)=82

8 X x/4 + 96+8 X -x/2=82

2x +96 +8 X -x/2=82

2x +96+ 8(-1)/2=82

2x +96 -8x/2 =82

2x+96-4x=82

-2x+96=82

-2x=-14

x=7

plz like and rate thank you

kirill115 [55]2 years ago
7 0
Answer X=7
Here is the answers for the question

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Find x: 3/(x-4)(x-7) + 6/(x-7)(x-13) + 15/(x-13)(x-28) - 1/x-28 = -1/20
Novay_Z [31]

The value of x<em> </em>in the polynomial fraction 3/((x-4)•(x-7)) + 6/((x-7)•(x-13)) + 15/((x-13)•(x-28)) - 1/(x-28) = -1/20 is <em>x </em>= 24

<h3>How can the polynomial with fractions be simplified to find<em> </em><em>x</em>?</h3>

The given equation is presented as follows;

\frac{3}{(x - 4) \cdot (x - 7) }  + \frac{6}{(x - 7) \cdot (x - 13)   }  + +\frac{15}{(x - 13) \cdot (x - 28) } - \frac{1}{(x - 28)  } =  -  \frac{1}{20}

Factoring the common denominator, we have;

\frac{3\cdot(x - 13) \cdot(x - 28) + 6 \cdot(x - 4) \cdot(x - 28)  + 15 \cdot(x - 4) \cdot(x - 7)  - (x - 4) \cdot (x - 7)\cdot(x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)}   + =  -  \frac{1}{20}

Simplifying the numerator of the right hand side using a graphing calculator, we get;

By expanding and collecting, the terms of the numerator gives;

-(x³ - 48•x + 651•x - 2548)

Given that the terms of the numerator have several factors in common, we get;

-(x³ - 48•x + 651•x - 2548) = -(x-7)•(x-28)•(x-13)

Which gives;

\frac{-(x - 7) \cdot(x - 28)\cdot (x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)}   + =  -  \frac{1}{20}

Which gives;

\frac{-1}{(x - 4)}   + =  -  \frac{1}{20}

x - 4 = 20

Therefore;

  • x = 20 + 4 = 24

Learn more about polynomials with fractions here:

brainly.com/question/12262414

#SPJ1

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Cornelia cut equal lengths of ribbon each 7/10 ft long. The ribbon was 3 1/2 ft long.How many pieces did Cornelia cut?
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Answer:

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8 0
3 years ago
Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

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