a) –a + b is negative
b) a – b is positive
c) b-a is negative
Step-by-step explanation:
1. Suppose a and b are real numbers where a > 0 and b < 0.
a. Is –a + b positive or negative. Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
–a + b
= -(6)+(-5) = -6-5 = -11
So, –a + b is negative
b. Is a – b positive or negative? Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
a - b
=6-(-5) = 6+5 = 11
So, a – b is positive
c. Is b – a positive or negative. Explain how you know
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
b-a
=(-5)-(6)
= -5-6
= -11
So, b-a is negative
Keywords: Solving Integers:
Learn more about solving integers at:
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Answer:
hello dude you see um this is complicated
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let x represent the number of toys that each club member donated.
There are 9 students in a service club.
If each club member donated 4 children's books for the baskets, it means that the total number of books donated by the club members would be
9 × 4 = 36
If each club member also donated an equal number of toys. It means that the total number of toys donated by the club members would be
9 × x = 9x
A total of 63 items were collected for the baskets. Therefore, the linear equation that you can use to find how many toys each club member donated would be
9x + 36 = 63
7x^2 + 3
7(4)^2 + 3
7(16) + 3
112 + 3
115.
