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MaRussiya [10]
4 years ago
5

Suppose you draw a card from a well-shuffled pack of playing cards. What is the probability the card you draw will be an ace? A.

4/50 B. 1/13 C. 4/13 D. 1/52
Mathematics
1 answer:
zhenek [66]4 years ago
5 0
Sample space = {52 cards} = all possible outcomes
Favorable outcome ={ 4 Aces}

P(drawing ONE Ace) = 4/52 = 1/13 = 0.0769 (answer B. 1/13)
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How can you solve Stoichiometric Calculations
Llana [10]

Almost all stoichiometric problems can be solved in just four simple steps:

  1. Balance the equation.
  2. Convert units of a given substance to moles.
  3. Using the mole ratio, calculate the moles of substance yielded by the reaction.
  4. Convert moles of wanted substance to desired units.
3 0
3 years ago
How many times does christine tune up her bike each year
jekas [21]

80(miles) x 52(weeks in a year) = 4160(miles in a year)

4160 / 4(tunes in a year) = 1040(miles to go before a tune)

Now for Christine

100(miles) x 52(weeks in a year) = 5200(miles in a year)

5200 / 1040(miles to go before a tune) = 5(tunes in a year)

Answer C. 5

4 0
3 years ago
An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
4 years ago
Suppose 5 quarts of a solution that is15% antifreeze is mixed with quarts 3 of a solution that is antifreeze 65% . Answer the qu
dem82 [27]

1. .35(15) + .72(5) = 8.85

2.8.85/(15 + 5) = 0.4425 = 44.25%Answer:

Step-by-step explanation:

3 0
3 years ago
I needed to write something long enough
borishaifa [10]

Answer:

The 1st problem it is the Last Graph

The 2nd problem it is the First Graph

6 0
2 years ago
Read 2 more answers
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