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Thepotemich [5.8K]
3 years ago
7

The product of two numbers is 10000.If one number is 16 times the other numbers ,find the two numbers.​

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Answer:

  • (25, 400) or (-25, - 400)

Step-by-step explanation:

Let the numbers be x and y.

<u>We have:</u>

  • y = 16x
  • xy = 10000

<u>Substitute y and solve for x:</u>

  • x(16x) = 10000
  • 16x² = 10000
  • x² = 10000/16
  • x² = 625
  • x = √625
  • x = ± 25

<u>Then y is:</u>

  • y = ± 25*16 = ± 400

<u>The numbers are:</u>

  • 25 and 400 or -25 and - 400
Simora [160]3 years ago
5 0

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

<h2>➯Question:</h2>

  • The product of two numbers is 10000. If one number is 16 times the other numbers ,find the two numbers.

<h2>Answer:</h2>

  • Both numbers are 25 and 400.

<h3>Step By Step Explanation:</h3>

<h3>Given that:</h3>

  • The product of two numbers is 10000.

  • One number is 16 times the other number.

<h3>To Find:</h3>

  • Both numbers?

<h3>Solution:</h3>

  • Let us consider that one number be n, in question it is stated that other number is 16 times the first number. Therefore, other number is 16n.

<h3>According to the Question :</h3>

\sf↦ Product ~of ~numbers = 10000\\\\↦ n × 16n = 10000\\\\↦ 16n² = 10000\\\\↦ n² = \sf \dfrac{10000}{16}\\\\↦ \sf n = \sqrt{\dfrac{10000}{16}}\\\\↦ \sf n = \sqrt{\dfrac{100\:\times\:100}{4\:\times\:4}}\\\\↦ \sf n = {\cancel{\dfrac{100}{4}}}\\\\➦\pmb{\underline{\boxed{\sf{\pink{n = 25}}}}}

<h3>Hence,</h3>

  • 1st number = n = 25

  • 2nd number = 16n = 16 × 25 = 400

<h3>∴ Hence, both numbers are 25 and 400.</h3>

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

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Anvisha [2.4K]

Hi there! Let me know if you have questions about my answer:

One shrub is $11.

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Step-by-step explanation:

To find the cost of each item, write a system of equations, one equation for what each person bought, and solve for each variable.

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<u>Create a system using the variables and information from the question.</u>

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<u>Solve the system.</u>

I will solve the system algebraically, using the substitution method. Isolate one variable in one of the equations.

I will isolate 'd' in Jessica's equation:

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\frac{2d + 11r}{2} = \frac{129}{2}                  Divide everything in the equation by 2

d + \frac{11r}{2} = \frac{129}{2}                 Simplify

d = \frac{129}{2} - \frac{11r}{2}                 Isolate 'd' by subtracting \frac{11r}{2} from both sides.

Now you have an expression for 'd'.

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5d + 7r = 97                      Start with Arjun's equation

5(\frac{129}{2} - \frac{11r}{2}) + 7r = 97       Substitute 'd' for  d = \frac{129}{2} - \frac{11r}{2}

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Substitute 'r' for 11 using either Arjun's or Jessica's equation. Then, isolate 'd' to solve for the cost of one daylily.

I will use Arjun's equation.

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5d + 77 = 97                   Simplify. Subtract 77 from both sides.

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I hope this helped! Check out a similar problem about solving systems here to learn more:

brainly.com/question/11103098

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