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3 years ago

Volume of a square with a diameter of 9

Mathematics

2 answers:

goldenfox [79]3 years ago

6 0

Answer:

The answer is 81.

Step-by-step explanation:

To find volume, you multiply the length by width. (Diameter by the side) Basically, 9*9=81

Hope this helps!

Phantasy [73]3 years ago

3 0

Answer:

729

Step-by-step explanation:

A square does not have a diameter so I am assuming that a side length is 9. If that is true all you must do is multiply 9x9x9

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The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inche

mash [69]

Answer:

6,4

Step-by-step explanation:

I'm not sure if 4 is correct but 6 definitely is. I hope this helps

3 0

1 year ago

kittens weigh about 100 grams when they are born and gain seven to 15 grams per day if a kitten weighed 100 grams at Birth and g

pickupchik [31]

100x3=300
300-100=200
200÷8= 25 days

5 0

3 years ago

8. Solve for x. Round your answer to the nearest tenth. 8.6 4 x 0176

earnstyle [38]

Answer:

C. 9.5

Step-by-step explanation:

The Pythagorean Theorem: a^2 + b^2 = c^2.

4^2 + 8.6^2 = c^2

16 + 73.96 = c^2

c^2 = 89.96

c = 9.4847....

8 0

2 years ago

Define the axis of symmetry, vertex, focus and directrix for

Papessa [141]

Answer:

see attached

Step-by-step explanation:

The equation is in the form ...

4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance

Comparing this to your equation, we see ...

p = 4, (h, k) = (3, 4)

p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...

vertex: (3, 4)

axis of symmetry: x = 3

focus: (3, 8) . . . . . 4 units up from vertex

directrix: y = 0 . . . horizontal line 4 units down from vertex

8 0

2 years ago

What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?

Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

SOLUTION:

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)

We know that, distance between two points $P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right)$ is given by

$P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now,

$\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}$

8 0

2 years ago