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Keith_Richards [23]
3 years ago
12

Suppose A and B are points. How many lines contain both A and B?

Mathematics
2 answers:
spayn [35]3 years ago
7 0
One and only one line contains both A and B (assuming, that A and B do not overlap)
seraphim [82]3 years ago
6 0
Point A and point B should both contain one line
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A music website charges x dollars for individual songs and y dollars for entire albums. Person A pays $25.92 to download 6 indiv
kati45 [8]
Amount charged for downloading individual songs = x dollars
Amount charged for downloading an entire album = y dollars
In respect to person A:
6x + 2y = 25.92
3x + y = 12.96
y = 12.96 - 3x
In respect to person B:
4x + 3y = 33.93
Putting the value of y from the first equation in the second, we get
4x + 3(12.96 - 3x) = 33.93
4x + 38.88 - 9x = 33.93
- 5x = - 4.95
x = 0.99 dollars
Putting the value of x in the first equation, we get
y = 12.96 - 3x
   = 12.96 - 2.97
   = 9.99 dollars

7 0
3 years ago
There are 12 books on a shelf 5 of these books are new the rest are used what is the ratio of new books to used books
tiny-mole [99]

Answer:

5:7

Step-by-step explanation:

Basically you first find the amount of the books are the shelf knowing that you have 5 new books, you subtract the amount of new books from total books. And 5:7 can't be simplified any further making 5:7 the answer.

5 0
3 years ago
Read 2 more answers
Point D is 1/2 of the distance between which two points?
USPshnik [31]

Answer:

B and E

Step-by-step explanation:

B = - 6, D = - 2, E = 2

d(B, D) = - 2-(-6)= - 2 + 6 = 4 units

d(D, E) 2 - (-2) = 2 + 2 = 4

Since, d( B, D) = d( D, E)

Therefore, Point D is 1/2 of the distance between B and E.

5 0
3 years ago
Lifetime Fitness charges $90 a month for membership plus $50 per session with a trainer. Which equation can be used to determine
Taya2010 [7]

Answer:

50x / 30/x i think

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Please help!! Write in simplest radical form: √7/8 Show how you figured it out
12345 [234]

Given expression: \sqrt{\frac{7}{8}}.

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

=\frac{\sqrt{7}}{\sqrt{8}}

\sqrt{8}=\sqrt{2^2\cdot \:2}=2\sqrt{2}

\frac{\sqrt{7}}{\sqrt{8}} =\frac{\sqrt{7}}{2\sqrt{2}}

\mathrm{Rationalize\:}\frac{\sqrt{7}}{2\sqrt{2}}

\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{2}}{\sqrt{2}}

=\frac{\sqrt{7}\sqrt{2}}{2\sqrt{2}\sqrt{2}}

=\frac{\sqrt{14}}{4}

=\frac{\sqrt{14}}{4}.

3 0
3 years ago
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