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Lostsunrise [7]
3 years ago
10

The amount of money that Kelly makes varies directly with the number of hours she works. If Kelly makes $306 when she works 18 h

ours, what is the constant of variation for her earnings?
A) 15

B) 17

C) 18

D) 20
Mathematics
2 answers:
mash [69]3 years ago
4 0
It would be B 17 because 306 divided by 18 would be 17
Neko [114]3 years ago
3 0
If u divide $306 by the 18hrs u get 17x x=$ boom $17/hr
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Nick had 34 bottles of water for his wrestling practice.
zepelin [54]

Answer:

No I disagree, because he had 34 bottles of water at the start but, when he finished he only has 1 left. 34-1=33 so in reality he drank 33 bottles of water.

Step-by-step explanation:

5 0
2 years ago
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The population of Weston is 4320. The town’s records show that 45 percent of the population are males, and 2 3 23 of these males
lbvjy [14]

Answer:

In Weston 1,296 males are married

Step-by-step explanation:

step 1

Find out the number of males

Multiply the total population by 45%

45\%=45/100=0.45

4,320(0.45)=1,944\ males

step 2

Find out the number of males that are married

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therefore

In Weston 1,296 males are married

7 0
3 years ago
Quinzel earns $1,254 each month. His total deductions are 20% of his pay. How much is deducted from his pay each month? A. $62.7
Blababa [14]
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6 0
3 years ago
Why do we use variables in math?
Phoenix [80]

Answer:

We use it to substitute an unknown number. We have a variable for a number we don’t know and as we solve the problem we can find the answer for the variable or unknown number.

Step-by-step explanation:

I hope it helps! Have a great day!
Anygays-

8 0
1 year ago
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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?
omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

T_5 = 160

T_7 = 40

Required

T_6

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

\frac{T_7}{T_5} = \frac{40}{160}

Divide the numerator and the denominator of the fraction by 40

\frac{T_7}{T_5} = \frac{1}{4} ----- equation 1

Recall that the formula of a GP is

T_n = a r^{n-1}

Where n is the nth term

So,

T_7 = a r^{6}

T_5 = a r^{4}

Substitute the above expression in equation 1

\frac{T_7}{T_5} = \frac{1}{4}  becomes

\frac{ar^6}{ar^4} = \frac{1}{4}

r^2 = \frac{1}{4}

Square root both sides

r = \sqrt{\frac{1}{4}}

r = ±\frac{1}{2}

Next, is to solve for the first term;

Using T_5 = a r^{4}

By substituting 160 for T5 and ±\frac{1}{2} for r;

We get

160 = a \frac{1}{2}^{4}

160 = a \frac{1}{16}

Multiply through by 16

16 * 160 = a \frac{1}{16} * 16

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2560 = a

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

T_n = a r^{n-1}

Here, n = 6;

T_6 = a r^{6-1}

T_6 = a r^5

T_6 = 2560 r^5

r = ±\frac{1}{2}

So,

T_6 = 2560( \frac{1}{2}^5) or T_6 = 2560( \frac{-1}{2}^5)

T_6 = 2560( \frac{1}{32}) or T_6 = 2560( \frac{-1}{32})

T_6 = 80 or T_6 = -80

T_6 =±80

Hence, the 6th term is positive/negative 80

8 0
2 years ago
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