For this case we have the following domain:
{1, 3, 5, 7}
We have the following range:
{2, 4, 6}
A value of the range belongs to each value of the domain.
Therefore, the ordered pairs are:
(1, 2)
(3. 4)
(5, 6)
Answer:
A. {(1, 2), (3, 4), (5, 6), (7, 2)}
15 servings because 11.25/0.75=15
3/4=.75
11 1/4=11.25
Answer:[m, m+d, m+2d, - - - - -, n]
Step-by-step explanation:
We know the formula for arithmetic progression is a_(n) = a_(1) + (n-1)d
Where a_(n) is the nth term of the sequence
a_(1) is the first term of the sequence
n is the number of the term like if we are talking about 7th term so the n is 7.
d is the difference between two successive terms.
For this problem we know our first term that is m, our last term that is n and our difference that is d.
For second term we will use the formula
a_(2) = m + (2-1)d
a_(2) = m + (1)d
a_(2) = m + d
Similarly,
a_(3) = m + (3-1)d
a_(3) = m + (2)d
a_(3) = m + 2d
6 under par is written as -6
2 over par is written as 2
even par is written as 0
even par is written as 0
Total score: add all the numbers together:
-6 + 2 + 0 + 0 = -4 ( 4 under par).
Answer:
Its C it must be true
Step-by-step explanation: