Help again please i need to pass this
2 answers:
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Answer: a.) 72 of each type of animal, for a total of 216
b.) 16 grown cats, 4 kittens
Step-by-step explanation:
part a. It's a distribution (division) problem. The same number of each animal is distributed over some unknown number of troughs, but the total number of troughs adds up to 69. ( I hate to give this all away, as its a brilliant problem! )
Number of troughs for each animal type is How many needed by the number of animals per trough:
h/2 + c/3 + p/8 = 69
Since we are given "the same number of horses, cows and pigs" we can substitute "x" for all.
Get a common denominator. 24 would work, 48 also.
24x + 16x + 6x = 3372
46x = 3372 x = 72
Proof: calculate the number of each kind of trough
Horses 72/2 = 36, Cows 72/3 = 24 Pigs 72/8 = 9 36+24+9 = 69
part b. 5c + 3k = 92, c + k = 20 Rearrange to get a value for c to substitute.
c = 20-k 5(20-k) +3k =92 Distribute and solve
100 - 5k + 3k = 92 becomes -2k = -8 so k = 4 Substitute into the original
c + 4 = 20 becomes c=20-4, so c = 16
Proof: 5c +3k = 92 Substitute values 5(16) + 3(4) = 92 80 + 12 = 92
Tim has completed greater amount of work and overall they have completed 142/143 of the project work
Step-by-step explanation:
Given
Work completed by Jaime = j = 5/11
Work completed by Tim = t = 7/13
<u>a. Who has completed the greater amount of work?</u>
In order to see that we have to convert the fractions in decimal
So,
j = 5/11 = 0.45
t = 7/13 = 0.53
As we can see that the decimal for Tim's work space is large, Tim has completed greater amount of work
b. How much of the project have they completed together? Show your work.
We have to find the total work done by them
Hence,
Tim has completed greater amount of work and overall they have completed 142/143 of the project work
Keywords: Fractions, LCM
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