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KATRIN_1 [288]
3 years ago
6

Which number makes the equation true?

Mathematics
2 answers:
34kurt3 years ago
8 0

Answer: 1/6

Step-by-step explanation:

MrRa [10]3 years ago
5 0

Answer:

6 is the answer

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Whats an equation that the passes through (-6,4) and is parallel to y=1/2x+8
Trava [24]
Formula y-y1= m(X-X1)
Since its parallel the m is 1/2
The -6 is X1 and the 4 is y1
Okay now do formula

Y-4= 1/2(X--6)
Y-4= 1/2X+3
Add 4

Y= 1/2x +7
6 0
3 years ago
(x+12) (3x+2)<br> Find the value of X
KatRina [158]

Step-by-step explanation:

Equation at the end of step 1

(3x2 - 38x) + 24 = 0

STEP2:Trying to factor by splitting the middle term

 2.1     Factoring  3x2-38x+24 

The first term is,  3x2  its coefficient is  3 .

The middle term is,  -38x  its coefficient is  -38 .

The last term, "the constant", is  +24 

Step-1 : Multiply the coefficient of the first term by the constant   3 • 24 = 72 

Step-2 : Find two factors of  72  whose sum equals the coefficient of the middle term, which is   -38 .

     -72   +   -1   =   -73     -36   +   -2   =   -38   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -36  and  -2 

                     3x2 - 36x - 2x - 24

Step-4 : Add up the first 2 terms, pulling out like factors :

                    3x • (x-12)

              Add up the last 2 terms, pulling out common factors :

                    2 • (x-12)

Step-5 : Add up the four terms of step 4 :

                    (3x-2)  •  (x-12)

             Which is the desired factorization

Equation at the end of step2:

(x - 12) • (3x - 2) = 0

STEP3:Theory - Roots of a product

 3.1    A product of several terms equals zero. 

 When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 We shall now solve each term = 0 separately 

 In other words, we are going to solve as many equations as there are terms in the product 

 Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

 3.2      Solve  :    x-12 = 0 

 Add  12  to both sides of the equation : 

                      x = 12

Solving a Single Variable Equation:

3 0
4 years ago
Read 2 more answers
Show that if S1 and S2 are subsets of a vector space V such that S1 c S2 then span(S1) c span(S2). In particular, if S1 c S2 the
klemol [59]

Answer:

See proof below

Step-by-step explanation:

Assume that V is a vector space over the field F (take F=R,C if you prefer).

Let x\in span(S_1). Then, we can write x as a linear combination of elements of s1, that is, there exist v_1,v_2,\cdots,v_k \in S_1 and a_1,a_2,\cdots,a_k\in F such that x=a_1v_1+a_2v_2+\cdots+a_kv_k. Now, S_1\subseteq S_2 then for all y\in S_1 we have that y\in S_2. In particular, taking y=v_j with j=1,2,\cdots,k we have that v_j\in S_2. Then, x is a linear combination of vectors in S2, therefore x\in span(S_2). We conclude that span(S_1)\subseteq span(S_2).

If, additionally  S_2\subseteq S_1 then reversing the roles of S1 and S2 in the previous proof, span(S_2)\subseteq span(S_1). Then span(S_1)\subseteq span(S_2)\subseteq span(S_1), therefore span(S_1)=span(S_2).

5 0
3 years ago
Suzanne ran 4.5 miles for the school fundraiser. She earned $2.40 per mile. How much money did she make?
pochemuha

Answer:

the answer is $10.

$2.40=1

n=4.5

= 4.5×2.40

=$10.80

7 0
3 years ago
What theorem can be used to prove that the two triangles are congruent?
maw [93]

AAS(angle-angle-side), SSS(side-side-side), SAS(side-angle-side), ASA(angle-side-angle), and HL(hypotenuse-length)

7 0
4 years ago
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