Place the following in least to greatest. 3.24,3.45,3.429,3.024,3,5

Write the real form of each complex equation.

Lerok [7]

Answer:

Step-by-step explanation:

Given

(a) $z=4\cos (\theta )+9i\sin (\theta )$

$Re(z)=4\cos \theta$

$Im(z)=9\sin \theta$

(b) $z=6\cos (\theta )+i\sin (\theta )$

$Re(z)=6\cos \theta$

$Im(z)=\sin \theta$

(c) $z=\sqrt{5}\cos (\theta )+\sqrt{10}i\sin (\theta )$

$Re(z)=\sqrt{5}\cos (\theta )$

$Im(z)=\sqrt{10}\sin (\theta )$

(d) $z=5-2i+4\cos (\theta )+7i\sin (\theta )$

$z=5+4\cos \theta +i(7\sin \theta -2)$

$Re(z)=5+4\cos \theta$

$Im(z)=7\sin \theta -2$

5 0

3 years ago

HELP plZZZZZZZ<br> and THANK YOU

Artyom0805 [142]

$\huge \bf༆ Answer ༄$

Let's solve ~

Y - intercept of the line is the point where value of x is 0 [ where the line cuts y - axis ]

$\qquad \leadsto\sf \: (0 , 3)$

X - intercept of the line is at the point where value of y is 0

[ where the line cuts x - axis ]

$\qquad \leadsto\sf \: (1 , 0)$

3 0

2 years ago

Read 2 more answers

Please help. Cleary show what the slope and y-intercept are for each problem. An explanation would be nice, but I'm not going to

Romashka-Z-Leto [24]

Answer:

7: Slope: -2/3

8: y-intercept: (0,6)

9: Slope: -2

10: y-intercept: (0,4)

6 0

3 years ago

PLEASE HELP, ITS URGENT I WILL GIVE BRAINLY...

Liono4ka [1.6K]

Answer:

Cost of the box of pencils = x = $4

Cost of the notebook = x+2 = 4+2 = $6

Cost of package of pens = 3x = 3(4) = $12

Step-by-step explanation:

Let the cost of the box of pencils = x

Cost of the notebook = 2 more than the pencils cost = x+2

Cost of package of pens = 3 times the pencils cost = 3x

The total was $22, so we can say:

(x)+(x+2)+(3x) = 22

5x=22-2

x=20/5

x=$4

Cost of the box of pencils = x = $4

Cost of the notebook = x+2 = 4+2 = $6

Cost of package of pens = 3x = 3(4) = $12

6 0

3 years ago

(01.03 MC)<br> Which of the following is a step in simplifying the expression<br> (Xy^4/x^-5y^5)^3

Sati [7]

$\displaystyle\tt\left(\frac{xy^4}{x^{-5}y^5}\right)^{-3} =\frac{x^{-3}y^{4\cdot(-3)}}{x^{-5\cdot(-3)}y^{5\cdot(-3)}}=\boxed{\tt\frac{x^{-3}y^{-12}}{x^{15}y^{-15}}}$

4 0

3 years ago