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3 years ago

What x what gives me 49 but when you add it it gives me 14

1 answer:

3 0

7 because 7 x 7 is 49 but if you add 7 and 7 it gets to 14 7 is the answer
so if you do a different number you will be wrong

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Please help 20 points to who ever can

mixer [17]

Answer:

how is your mom doing tell her last night was crazy :D

Step-by-step explanation:

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3 years ago

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a girl spends 1/2of her money in a store. then she goes to another 1/2 of which was left with her. after she has rs 24 with how

zhuklara [117]

1/12

24 divided by 2 = 12

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3 years ago

The side of a square is 2X unites. Select the expression that represents the area

Aneli [31]

Answer:

6x x 6x

Step-by-step explanation:they are all actually like terms so just add then together and the multiply this

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3 years ago

I need help with this ASAP

liraira [26]

gg I dont now

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2 years ago

Find the derivative of f(x)= (e^ax)*(cos(bx)) using chain rule

Vikentia [17]

$f(x) = e^{ax}\cos(bx)$

then by the product rule,

$f'(x) = \left(e^{ax}\right)' \cos(bx) + e^{ax}\left(\cos(bx)\right)'$

and by the chain rule,

$f'(x) = e^{ax}(ax)'\cos(bx) - e^{ax}\sin(bx)(bx)'$

which leaves us with

$f'(x) = \boxed{ae^{ax}\cos(bx) - be^{ax}\sin(bx)}$

Alternatively, if you exclusively want to use the chain rule, you can carry out logarithmic differentiation:

$\ln(f(x)) = \ln(e^{ax}\cos(bx)} = \ln(e^{ax})+\ln(\cos(bx)) = ax + \ln(\cos(bx))$

By the chain rule, differentiating both sides with respect to <em>x</em> gives

$\dfrac{f'(x)}{f(x)} = a + \dfrac{(\cos(bx))'}{\cos(bx)} \\\\ \dfrac{f'(x)}{f(x)} = a - \dfrac{\sin(bx)(bx)'}{\cos(bx)} \\\\ \dfrac{f'(x)}{f(x)} = a-b\tan(bx)$

Solve for <em>f'(x)</em> yields

$f'(x) = e^{ax}\cos(bx) \left(a-b\tan(bx)\right) \\\\ f'(x) = e^{ax}\left(a\cos(bx)-b\sin(bx))$

just as before.

4 0

3 years ago