3:8 can also be written as 3/8
12:32 can also be written as 12/32
So thus 3:8 is equivalent to 12:32
Answer:
n = 60.22
Step-by-step explanation:
Hello
To find Sn, we need to draw out equations for each a₇ and a₁₉
In an arithmetic progression,
Sn = a + (n-1)d
Where Sn = sum of the A.P
a = first term
d = common difference
a₇ = 32
32 = a + (7-1)d
32 = a + 6d ........equation (i)
a₁₉ = 140
140 = a + (19-1)d
140 = a + 18d .........equation (ii)
Solve equation (i) and (ii) simultaneously
From equation (i)
32 = a + 6d
Make a the subject of formula
a = 32 - 6d .....equation (iii)
Put equation (iii) into equation (ii)
140 = (32 - 6d) + 18d
140 = 32 - 6d + 18d
Collect like terms
140 - 32 = 12d
12d = 108
d = 108 / 12
d = 9
Put d = 9 in equation (i)
32 = a + 6(9)
32 = a + 54
a = 32 - 54
a = -22
When Sn = 511
Sn = a + (n - 1)d
Substitute and solve for n
511 = -22 + (n-1) × 9
511 = -22 + 9n - 9
511 = -31 + 9n
511 + 31 = 9n
542 = 9n
n = 542 / 9
n = 60.22
20 p + 5p
10 p + 10p + 5p
10p + 10p + 1p + 1p + 1p +1p +1p
20p + 1p + 1p + 1p + 1p + 1p
2p + 2p + 2p + 2p + 2p + 2p +2p +2p + 2p + 2p + 2p + 2p + 1p
Answer:
The best prediction for the number of times a 4 will be drawn from the pile is:
125
Step-by-step explanation:
It is given that:
A set of cards contains cards numbered 1 – 8.
So, the theoretical probability that 4 comes up is:
Ratio of Number of favorable outcome( outcome of 4) to the total umber outcome(i.e. 8 )
Hence, Theoretical Probability that 4 is drawn=1/8
Now, out of 1000 trials the best prediction of number of times 4 is drawn is:
(The probability of drawing 4)×(Number of experiments or trials)
=(1/8)×1000
=125
