It should be 11. hope this helps :)
Answer:
Hence proved △ABE∼△CBF.
Step-by-step explanation:
Given,
ABCD is a parallelogram.
BF ⊥ CD and
BE ⊥ AD
To Prove : △ABE∼△CBF
We have drawn the diagram for your reference.
Proof:
Since ABCD is a parallelogram,
So according to the property of parallelogram opposite angles are equal in measure.
⇒1
And given that BF ⊥ CD and BE ⊥ AD.
So we can say that;
⇒2
Now In △ABE and △CBF
∠A = ∠C (from 1)
∠E = ∠F (from 2)
So by A.A. similarity postulate;
△ABE∼△CBF
Answer:
what line?
Step-by-step explanation:
Answer:28.6
I started by seeing how many 2.4 can go into 68.64. I found that it is pretty easy to find that if you multiply the 2.4 by ten you get 24 so we do that twice and have 48. We then subtract 48 from the 68.64 which leaves us with 20.64. If we multiply 2.4 by 5 we get 12 so once again subtract 12 from that 20.64 and now we are left with 8.64. So now we need to figure out how many more 2.4 are left well it is more than three because three gives us 7.2 so let’s subtract that from it now we are left with 1.44. Now we need to find out what times 2.4 gives us 1.44. Well it would be .6. So now if we add up everything we get the answer of 28.6. Sorry if this very complicated