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vlada-n [284]
3 years ago
14

In a grid of a backyard, the vertices of a garden are (20, 45), (40, 45), (40, 30), and (20, 30). The coordinates are measured i

n feet. Find the perimeter of the garden.
it said 14 was wrong so i dont know
Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

300 units

Step-by-step explanation:

You did the steps correctly, but you forgot that it does not go by 1s, but goes by 5s. Check your grid!

(I messed up on this too! ^^)

Hope this helps!

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How do i graph -7x-2y=-21???
ExtremeBDS [4]

Answer:

-7/2 is the slope. -10.5 is your starting point on the y-axis. You go from -10.5, up 7 and over to the left 2 times because it's negative.

Step-by-step explanation:

-7x-2y=-21

-2y=7x-21

y=-7/2x-21/2

y=-7/2x-10.5

Hope this helps!

7 0
3 years ago
Read 2 more answers
1.25+3/4+4/10+2 x 3/8+ 1.6
kari74 [83]

Answer:

(3x/4) + 4

Step-by-step explanation:

convert al to decimal and then add

1.25 + 0.75 +0 .4 + 2x 0.375 + 1.6

7 0
3 years ago
X^2-x-20 how do I write that in factored form
Rufina [12.5K]

Answer:

(x+4)(x-5)

Step-by-step explanation:

You need to find two numbers that multiply to be -20 but add up to be -1.

4 0
3 years ago
Read 2 more answers
Is this correct ? check plsss...
d1i1m1o1n [39]
This looks one hundred percent correct to me and to check your answer you can plug in the answer you find to the first equation 


17=37+4f 
17=37+4(-5)
17=37-20
17=17 

great job!!
7 0
3 years ago
Read 2 more answers
(a) How many integers in the range 1 through 120 are integer multiples of 2, 3, or 5? keyboard_arrow_down Solution (b) How many
Umnica [9.8K]

Answer:

(a) 88 integers

(b) 92 integers

Step-by-step explanation:

(a) integers whose last digits are divisible by 2 are multiples of two or numbers whose digits ends with zero. So for number 1-120 , all the even numbers which are sixty in number are are multiples of two.

For  3, numbers whose digits sum is divisible by three are multiples of three. 3,6,9,12,15,18,21,24,27,30 are multiples of three from numbers 1-30. we have four 30s in 120. which means numbers of integers will be 10*4 = 40integers. However out of these numbers , half are also integers of 2 which reduces the number added to 20integers.

For 5, numbers whose digits ends with 5 or 0 are multiples of 5. this gives us 24 integers for 1-120. but out of these 24integers, 16 are common integers of 2 and 3 which reduces the number added to 8integers.

Thus from 1-120 the intergers of 2,3 or 5 = 60+20+8 = 88integers.

(b) if we are considering from numbers 1-140;

for 2 we wil have 70 integers,

for 5 we will have 28 integers, but those integers that end with 0 are also integers of 2 which reduces the number added to 14.

For 7, numbers 7,14,21,28,35,42,49,56,63,70 are multiples of three from 1-70. This pattern is repeated from number 71-140. hence we have 20 integers in all. However 12 of the multiples are also multiples of either 2 or 5 which reduces the number to 8 integers.

Thus from 1-140, the integers of 2, 5, or 7 = 70+14+8 = 92integers

3 0
3 years ago
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