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3 years ago

Q1) f(x) = 2x^2 - 5x, g(x) 3x^2 find f(2)

Mathematics

1 answer:

pashok25 [27]3 years ago

6 0

Answer:

f(2)= -2

g(2)= 12

Step-by-step explanation:

To solve this we use the substitution method. Since f(2) is your variable, we will plug the x-value of 2 into each equation

f(2)= 2(2)^2-5(2)

f(2)=8-10

f(2)= -2

If the same variable is used for both equations then g(x) would be g(2) as well leaving you with

g(x) = 3x^2

g(2)= 3(2)^2

g(2)=12

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2 years ago

If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH

olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

$\angle EFG=\angle EFH+\angle HFG$

$18x+11=(5x+1)+(62)$

$18x+11=5x+63$

Isolate variable terms.

$18x-5x=63-11$

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Divide both sides by 13.

$x=\dfrac{52}{13}$

$x=4$

The value of x is 4.

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$\angle EFH=(5(4)+1)^\circ$

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Therefore, the measure of ∠EFH is 21°.

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