1st find the averages of each one:
Elizabeth average of reading in min =(18+36+15+45+88+57+12)/7 =38.71 min
Sam average of reading in min =(17+52+48+35+13+71+16)/7 =36 min
question:
1) No
2) YES. [the range is te difference between the largest & the smallest)
Eliz Range = 88-12 =76 & Sam's= 71-13 = 58
3) NO. Sam 71 min & Eliz 88 min
4) YES. Median Eliz =45 min. Median Sam =35 min
Answer:
5/22
Step-by-step explanation:
A bag has 6 blue marbles, 4 red marbles, and 2 green marbles. Wo marbles are randomly chosen without replacement.
Total number of marbles =
6 blue marbles + 4 red marbles + 2 green marbles
= 12 marbles
The probability of picking a blue marble = P(B) = 6/12
Therefore, the probablilty that both marbles picked are blue without replacement is
= 6/12 × 5/11
= 30/132
= 5/22
Answer:
0.337 = 33.7% probability that one of the eight children has a food allergy.
Step-by-step explanation:
For each children, there are only two possible outcomes. Either they have a food allergy, or they do not. The probability of a child having food allergy is independent of any other child. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
7% of U.S. children 4 years of age or younger have a food allergy.
This means that
A day care program has capacity for 8 children in that age range.
This means that
What is the probability that one of the eight children has a food allergy?
This is P(X = 1).
0.337 = 33.7% probability that one of the eight children has a food allergy.
Answer:
?=14
Step-by-step explanation:
12+5=17
8+8=16
8+4х8=40
4+6х4=28
9-5=4
9-12+5+8+4=14