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antoniya [11.8K]
3 years ago
6

How many solution does this equation have -5j = -6j - 4

Mathematics
1 answer:
Nataly_w [17]3 years ago
6 0

Answer:

1

Step-by-step explanation:

All variable terms are to the first power. You can prove this by solving:

-5j = -6j - 4

4 = -1j

j = -4 (One answer)  

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Answer: 6x(x+2)
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Y=4x-2tan(x), (-pi/2,pi/2)<br> which are the relative min and max?
Jlenok [28]

relative max  = pi -2

relative min   = -2 pi

Step-by-step explanation:

y= 4x- 2tan(x), (-pi/2,pi/2)

To find relative max and min,

According to mathematical procedure to find relative max and relative min,

the following procedure should be carry out.

Derivating equation with respect to x,

          \frac{dy}{dx} =\frac{d}{dx}  (4\times x -2 \times tan x).....(1)

Equating equation (1) to Zero,

We get,

           0 =\frac{d}{dy}  (4\times x -2 \times tan x)

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           4 = 2 \times sec^{2}  x

           2 = sec^{2}  x

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There are total three points

1. -pi/2      2. pi/2      3. pi/4

checking local min and local max

first considering -pi/2;

                   \frac{d^{2}y  }{dx^{2} } =\frac{d^{2} }{dx^{2} }  (4\times x -2 \times tan x)...(2)

putting x= pi/4 in equation (2),

we get,      

                   \frac{d^{2}y  }{dx^{2} } = -4 <0      

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by putting value of x in equation (1);

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                 y =   4\times (\pi /4 ) -2 \times tan (\pi /4 )

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Similarly,  at  x= -pi/ 2,

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So, we have local min at x=-pi/2

by putting value of x in equation (1);

we get,

                 y =   4\times (-\pi /2 ) -2 \times tan (-\pi /2 )

                 y =  -2 \times \pi.... is minimum point

       

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Answer:

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