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AleksAgata [21]
4 years ago
10

A plane flew 2,190 kilometers from Chicago to Flagstaff. Another plane flew 2,910 kilometers from Chicago to Oakland. How much f

arther did the plane that flew to Oakland fly than the plane that flew to flagstaff?
Mathematics
2 answers:
stiv31 [10]4 years ago
4 0
720 kilometers farther
DiKsa [7]4 years ago
3 0
The answer is 720.hope it helps.
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X= 1/7, -4/3
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Step-by-step explanation:

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The mean for a data set is 60. The Z-score for
Vladimir [108]

Answer:

D. a = 60 and b = 58.8

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Z-score for data point a is 0.

This means that a is the mean, that is, a = 60.

The z-score for data point b is -0.4.

This means that b must be a value below the mean, that is, a value below 60.

The option that satisfies a = 60 and b < 60 is option D, which is the answer.

7 0
3 years ago
(12, 9, 4) What is the area of the parallelogram shown below?
zavuch27 [327]

area of the parallelogram is: b x h

12 x 4 = 48 (d)

7 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
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