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3 years ago

When 2 or more organisms compete for the same resource there can be a variety of outcomes. What would be one of those outcomes?

Biology

1 answer:

Pachacha [2.7K]3 years ago

7 0

Answer:

The biology branch deals with the relations between and physical environment of organisms.

Explanation:

The principle of competitive exclusion states that if two species occupy the same niche, they cannot exist together (competing for identical resources). Two species whose niche overlap can evolve to have different niches through natural selection, resulting in the distribution of resources.

In ecology, interspecific competition is a form of competition where individuals from different kinds compete in an ecosystem for the same resources (e.g. food or space)... There may be interspecific competition if people of two separate species share a limited resource within a single area.

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A cell of an organism has four chromosomes. It undergoes a process at the end of which two daughter cells are produced. Each dau

erma4kov [3.2K]

The answer would have to be Cytokinesis

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3 years ago

Organisms with the genotypes aabbccdd and aabbccdd are crossed. What are the expected proportions of the following progeny?

Dvinal [7]

Answer:

a) $\frac{27}{64}$

b) $\frac{1}{32}$

c) $\frac{27}{64}$

d) $\frac{3}{64}$

Explanation:

The correct question is

Organisms with the genotypes AABbCcDd and AaBbCcDd are crossed. What are the expected proportions of the following progeny?

a. A_B_C_D_

b. AabbCcDd

c. a phenotype identical to either parent

d. A_B_ccdd

Solution

In such question the probability for each allele pair is to be determines separately

For instance,

AA * Aa will produce AA, Aa, AA, Aa this means that all the the probability of getting both AA and Aa is $\frac{1}{2}$

Like wise when Bb and Bb are crossed, BB, Bb, Bb, and bb are produced. So the probability of getting dominant trait i.e BB or Bb is $\frac{3}{4}$ and recessive trait i.e bb is $\frac{1}{4}$

Chance to get homozygous bb only or BB only is $\frac{1}{4}$

and chance of getting Bb is $\frac{1}{2}$

Like Bb and Bb cross, the same will be the probabilities for Cc and Cc cross and Dd and Dd cross

Part A)

$\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}$

Part B)

$\frac{1}{4} * \frac{1}{2} * \frac{1}{2}* \frac{1}{2}\\= \frac{1}{32}$

Part C)

$\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}$

Part D)

$\frac{3}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{3}{64}$

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Hope it helped,

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