Answer:
The point is in the 4th quadrant.
Explanation:
Given the ordered pair(4, -5), we have that x = 4 and y = -5. Plotting this point, we'll have;
Note that quadrants are labelled in an anti-clockwise direction with the top right portion of the graph as the 1st quadrant. Looking at the plotted point, we can see that it i in the 4th quadrant.
Answer:
No
Step-by-step explanation:
For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.
I hope this helps! :)
The person has 1 5/6 cake left because 3 2/4 - 1 2/3 = 1 5/6! Hope this helps ^0^
Explanation
Rewriting Expression in different parts.
= 3 + 2/4 + 1 + 2/3.
Solving The Whole Number Parts.
3 + 1 = 4
Solving The Fraction Parts.
2/4 + 2/3 = ?
Find the LCD of 2/3 and 2/4 and Rewrite to solve with equivalent Fractions.
LCD = 12
6/12 + 8/12 = 14/12
Simplify the Fraction Part.
14/12 = 7/6
Simplify The Fraction Part Again.
7/6 = 1 1/6
Combining The Whole Numbers With The Fractions.
4 + 1 + 1/6 = 5 1/6
Hope this helps ^0^! ;D
Answer:
a) integral = 24.72
b) |Error| ≤ 0.4267
Step-by-step explanation:
a)
The integral:

can be approximated with the midpoint rule, as follows:
6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72
(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)
b)The error bound for the midpoint rule with <em>n</em> points is:
|Error| ≤ K*(b - a)^3/(24*n^2)
where <em>b</em> and are the limits of integration of the integral and K = max |f''(x)|
Given that -5 ≤ f''(x) ≤ 1, then K = 5. Replacing into the equation:
|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267