Answer:
6y (y + 4)
(pick out the common factors) \
hope its righ!
Answer:
t=4 seconds
Step-by-step explanation:
The height of the water jacket that is projected vertically upward is given by the equation:
![h = 20 - 5(t - 2)^{2}](https://tex.z-dn.net/?f=h%20%3D%2020%20-%205%28t%20-%202%29%5E%7B2%7D%20)
We want to find the time that, the rocket reaches the ground.
When the rocket reaches the ground, the height , h becomes 0.
This implies that:
![20 - 5(t - 2)^{2} = 0](https://tex.z-dn.net/?f=%2020%20-%205%28t%20-%202%29%5E%7B2%7D%20%20%3D%200)
Subtract 20 from both sides:
![- 5(t - 2)^{2} = - 20](https://tex.z-dn.net/?f=%20-%205%28t%20-%202%29%5E%7B2%7D%20%20%3D%20%20-%2020)
Divide through by -5;
![{(t - 2)}^{2} = 4](https://tex.z-dn.net/?f=%20%7B%28t%20-%202%29%7D%5E%7B2%7D%20%20%3D%204)
Take square root:
![(t - 2) = \pm \sqrt{4}](https://tex.z-dn.net/?f=%20%28t%20-%202%29%20%20%3D%20%20%5Cpm%20%5Csqrt%7B4%7D%20)
l
![(t - 2) = \pm 2 \\ t = 2\pm 2 \\ t = 2 - 2 \: or \: t = 2 + 2 \\ t = 0 \: or \: t = 4](https://tex.z-dn.net/?f=%28t%20-%202%29%20%20%3D%20%20%5Cpm%202%20%5C%5C%20t%20%3D%20%202%5Cpm%202%20%5C%5C%20t%20%3D%202%20-%202%20%5C%3A%20or%20%5C%3A%20t%20%3D%202%20%2B%202%20%5C%5C%20t%20%3D%200%20%5C%3A%20or%20%5C%3A%20t%20%3D%204)
Therefore the feasible time is after 4 seconds.
Can you take it out of spanish. I speak english
Step-by-step explanation:
y=a(x-h)+k
=6(-2-2)²+2
=6(16)+2
=98
Answer:
sinC = ![\frac{4\sqrt{41} }{41}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Csqrt%7B41%7D%20%7D%7B41%7D)
Step-by-step explanation:
We require to find the side DE before finding sinC
Using Pythagoras' identity in the right triangle
DE² + CE² = CD²
DE² + 5² = (
)²
DE² + 25 = 41 ( subtract 25 from both sides )
DE² = 16 ( take the square root of both sides )
DE =
= 4 , then
sinC =
=
=
, rationalise the denominator
sinC =
×
=