Well, the car depreciated in value by 12%, so you could say
x-12%, or just
x-0.12.
Answer:option 2
Step-by-step explanation:sets Band C contains 2,4,6 in common
Set A and the common set of B and C stated above contains 2 in common
Answer:
Part A: 25% of 50 = 12.5
Part B: 25% of 60 = 15
Part C: 50% of 60 = 30
Part D: 75% of 60 = 45
Part E: 75% of 30 = 22.5
Part F: 100% of 22.5 = 22.5
Part G: 10% of 22.5 = 2.25
Part H: 50% of 45.7 = 22.85
Step-by-step explanation:
To find - Do you know the answer to
Part A: 25% of 50 =
Part B: 25% of 60 =
Part C: 50% of 60 =
Part D: 75% of 60 =
Part E: 75% of 30 =
Part F: 100% of 22.5 =
Part G: 10% of 22.5 =
Part H: 50% of 45.7 =
Proof -
Part A :
25% of 50 =
=
= 12.5
⇒25% of 50 = 12.5
Part B :
25% of 60 =
=
= 15
⇒25% of 60 = 15
Part C :
50% of 60 =
=
= 30
⇒50% of 60 = 30
Part D :
75% of 60 =
=
= 45
⇒75% of 60 = 45
Part E :
75% of 30 =
=
= 22.5
⇒75% of 30 = 22.5
Part F :
100% of 22.5 =
= 22.5
⇒ 100% of 22.5 = 22.5
Part G :
10% of 22.5 =
= 2.25
⇒ 10% of 22.5 = 2.25
Part H :
50% of 45.7 =
=
= 22.85
⇒50% of 45.7 = 22.85
Total amount of money invested - $11500
X +Y = $11500. ----------(1)
Total yearly interest for thetwo a/c is - $201
-0.03X + 0.04Y = $201
Form (1)
X = 11500 - Y
Substitute for X
-0.03(11500 - Y) + 0.04 Y = $201
-345 + 0.03Y + 0.04Y =201
0.07Y = 546
Y = 7800 at 4 %
Calculate X
X = 11500 - Y
= 11500 - 7800
=3700 at - 3%
Check
-0.03×3700 + 0.04 × 7800 = $201
-111 + 312 = $201
$201 = $201
Answer:
x = 3
Step-by-step explanation:
6x + 2x - 5= 19
8X -5 = 19
8x = 24
x = 3