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olga nikolaevna [1]

2 years ago

12

A town's population has been growing linearly. in 2003 the population was 70,000. the population has been growing by 2700 people

each year. write an equation for the population, p, x x years after 2003.
Use the formula to find the population in 2009.

1 answer:

skad [1K]2 years ago

8 0

Answer:

86200

Step-by-step explanation:

2700*6

16200+70000

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Step-by-step explanation:

The Margin of Error is given as

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Rearranging this equation in terms of n gives

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Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as

$n_2=\left[z_{crit}\times \dfrac{\sigma}{M_2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{\sigma}{M/2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{2\sigma}{M}\right]^2\\n_2=2^2\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4n$

As n is given as 40 so the new sample size is given as

$n_2=4n\\n_2=4*40\\n_2=160$

So the sample size to obtain the desired margin of error is 160.

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