The least common multiple of each pair of the polynomial (5y² - 80) and
(y + 4) is equal to 5(y-4)(y+4).
As given in the question,
Given pair of the polynomial is (5y² - 80) and (y + 4)
Simplify the given polynomial using (a² -b²) = (a-b)(a +b)
(5y² - 80) = 5(y² -16)
⇒(5y² - 80) = 5(y² - 4²)
⇒(5y² - 80) = 5(y -4)(y + 4)
And (y + 4) = (1) (y+4)
Least common multiple = 5(y-4)(y+ 4)
Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).
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Note on how to solve such equation:
This is a quadradic equation. The figure shown is a parabola. This parabola opens downward. Now, this information is not necessary important for this particular situation; however, it needs to be retained for said class or for the near future.
The equation for a quadradic function is: f(x)=x^2+2
when x=-2, y=1
Answer:
x= 7/5 (1 2/5 or 1.4)
Step-by-step explanation:
Move the variable to the left-hand side and change its sign.
12x-15+3x=6
Move the constant to the right-hand side and change its sign.
12x+3x=6+15
Collect like terms.
15x=21
Divide both sides of the equation by 15.
x=7/5 (1 2/5 or 1.4)
