Answer:
I would need to see the grapgh
Step-by-step explanation:
First we join the two endpoints of the semicircle and that will be the diameter.
And to find the length of the diameter, we have to use distance formula, with one endpoint (3,2) and the other is (-4,-2) .
SO we get
![Diameter = \sqrt{ {-4-3)^2 +(-2-2)^2 } = \sqrt{49+16} = \sqrt 65](https://tex.z-dn.net/?f=%20Diameter%20%3D%20%5Csqrt%7B%20%7B-4-3%29%5E2%20%2B%28-2-2%29%5E2%20%7D%20%3D%20%5Csqrt%7B49%2B16%7D%20%3D%20%5Csqrt%2065%20)
Radius is half of diameter, so the radius is
![Radius= \frac{ \sqrt{65}}{2}](https://tex.z-dn.net/?f=%20Radius%3D%20%5Cfrac%7B%20%5Csqrt%7B65%7D%7D%7B2%7D%20)
Formula of area of circle is
![Area = \pi r^2](https://tex.z-dn.net/?f=%20Area%20%3D%20%5Cpi%20r%5E2%20)
So the area of semicircle is
![=(1/2) \pi ( \frac{ \sqrt{65}}{2})^2 = 8.125 \pi \square \units](https://tex.z-dn.net/?f=%20%3D%281%2F2%29%20%5Cpi%20%28%20%5Cfrac%7B%20%5Csqrt%7B65%7D%7D%7B2%7D%29%5E2%20%3D%208.125%20%5Cpi%20%5Csquare%20%5Cunits%20)
And the other figure is a triangle, with
![Base = 3-(-4)=3+4=7 \\ height = 2-(-2) = 2+2 =4](https://tex.z-dn.net/?f=%20Base%20%3D%203-%28-4%29%3D3%2B4%3D7%20%5C%5C%20height%20%3D%202-%28-2%29%20%3D%202%2B2%20%3D4%20)
![Area = (1/2)*4*7= 14 square units](https://tex.z-dn.net/?f=%20Area%20%3D%20%281%2F2%29%2A4%2A7%3D%2014%20square%20units%20)
Therefore, total area is the sum of area of semicircle and area of triangle,
And we will get
![Total \ area= 14 + 8.125 \pi \ units^2](https://tex.z-dn.net/?f=%20Total%20%5C%20area%3D%2014%20%2B%208.125%20%5Cpi%20%5C%20units%5E2%20)
Correct option is the third option .
The roots of an equation are simply the x-intercepts of the equation.
See below for the proof that
has at least two real roots
The equation is given as: ![\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7Bx%5E4%7D%7B2021%7D%20%3D%202021x%5E2%20-%20x%20-%203%20%3D%200%7D)
There are several ways to show that an equation has real roots, one of these ways is by using graphs.
See attachment for the graph of ![\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7Bx%5E4%7D%7B2021%7D%20%3D%202021x%5E2%20-%20x%20-%203%20%3D%200%7D)
Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)
From the attached graph, we can see that
crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500
This means that
has at least two real roots
Read more about roots of an equation at:
brainly.com/question/12912962
You are trying to find the side between the right angle and the degree (This is known as the adjacent)
You are given degree 42
You also given the longest side of 19 (This is known as the hypothenuse)
Cosine: adjacent/hypothenuse
Cos42 = x/19
0.7431448255 = x/19
x = 19 * 0.7431448255
x = 14.11975168, round to tenth
Solution: x = 14.1
70 flowers were planted in all.
Step-by-step explanation:
Let,
Tulips = t
Daises = d
Lilies = l
Total tulips planted = 42
She planted 2 times as many tulips as daises.
t=2d
Putting t=42
![42=2d\\2d=42](https://tex.z-dn.net/?f=42%3D2d%5C%5C2d%3D42)
Dividing both sides by 2
![\frac{2d}{2}=\frac{42}{2}\\d=21](https://tex.z-dn.net/?f=%5Cfrac%7B2d%7D%7B2%7D%3D%5Cfrac%7B42%7D%7B2%7D%5C%5Cd%3D21)
And 3 times as many daisies as lilies.
d=3l
Putting d=21
![21=3l\\3l=21](https://tex.z-dn.net/?f=21%3D3l%5C%5C3l%3D21)
Dividing both sides by 3
![\frac{3l}{3}=\frac{21}{3}\\l=7](https://tex.z-dn.net/?f=%5Cfrac%7B3l%7D%7B3%7D%3D%5Cfrac%7B21%7D%7B3%7D%5C%5Cl%3D7)
Total flowers planted = Tulips + Daisies + Lilies
Total flowers planted = 42 + 21 + 7 = 70
70 flowers were planted in all.
Keywords: division, addition
Learn more about addition at:
#LearnwithBrainly