Answer:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Step-by-step explanation:
Equation I: 4x − 5y = 4
Equation II: 2x + 3y = 2
These equation can only be solved by Elimination method
Where to Eliminate x :
We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I
Hence:
Equation I: 4x − 5y = 4 × 2
Equation II: 2x + 3y = 2 × 4
8x - 10y = 20
8x +12y = 6
Therefore, the valid reason using the given solution method to solve the system of equations shown is:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
The answer is 1.81 repeated so like 1.81818181
Answer:
7x-5 = 9
x = 2
Step-by-step explanation:
Let x be the number
7x-5 = 9
Add 5 to each side
7x-5+5 = 9+5
Divide each side by 7
7x = 14
7x/7 = 14/7
x=2
The green arrow thing is a ray. So, question b. is a ray. So the dot would be B and the arrow would be C.
It’s b :) haha i got it right
