LPPLSSSSS HELP MEE ASAPPPP

Johann uses 42 ÷ 7 to represent the number of players who are on teams. Explain what 42 ÷ 7 means. Enter a number in each box. 4

ankoles [38]

42 players are on teams in all and that each team has 6 players. This is correct if the number 7 is referring to the number of teams.

8 0

3 years ago

PLEASE HELP! I'LL GIVE BRAINLIEST:)

Taya2010 [7]

Step-by-step explanation:

We know that if (h,k) is the center of any circle and whose radius is = r then its equation is :

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

Given, the equation of circle

${(x + 2)}^{2} + (y - 3) ^{2} = 25 = {5}^{2}$

By comparing, we will get,

h = -2

k = 3

So, center of the circle is ( -2,3)

$\large \green{ \: \: \: \: \boxed{\boxed{\begin{array}{cc} \bf\:Mark\\\bf\:me\:as\\\bf brainliest \end{array}}}} \\$

5 0

3 years ago

Read 2 more answers

12. The weight of 56 books is 8kg. What is the weight of 154 such books?

Korvikt [17]

Answer:

56+56=112 16kg

112+42=154 42 = 6kg

Step-by-step explanation:

5 0

3 years ago

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0

3 years ago

What is t if 3/5=2/3t.

Dvinal [7]

т = 9/10

Я сподіваюсь допомогла ^ - ^

6 0

3 years ago