All categories

3 years ago

15% of the fruit in a basket are apples. If there are 3 apples, how many pieces of fruit are there in the basket? HELP ASAP

Mathematics

1 answer:

xxMikexx [17]3 years ago

5 0

Answer:

the answer is 20 apples.

Step-by-step explanation:

15/100 is simplified down to 3/20, so therefore you have three apples out of 20. 20 is your total amount of apples.

You might be interested in

Pls help due in 10 minutes!!!!!!!!!!!!!!1

AlladinOne [14]

Answer:

Step-by-step explanation:

Given expression:

$27 \cdot \left(\left(3^3\right)^{-1}\right)$

Following the <u>order of operations</u>, carry out the operations inside the parentheses first:

$\implies 27 \cdot \left(\left(3 \cdot 3\cdot 3\right)^{-1}\right)$

$\implies 27 \cdot \left(27^{-1}\right)$

$\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:$

$\implies 27 \cdot \left(\dfrac{1}{27^1}\right)$

$\implies 27 \cdot \left(\dfrac{1}{27}\right)$

Convert 27 to a fraction:

$\implies \dfrac{27}{1} \cdot \dfrac{1}{27}$

Cross cancel the common factor:

$\implies \dfrac{\diagup\!\!\!\!\!27}{1} \cdot \dfrac{1}{\diagup\!\!\!\!\!27}$

$\implies \dfrac{1}{1}$

$\implies 1$

5 0

2 years ago

HELPPPP

SOVA2 [1]

Answer:

triangle 4

Step-by-step explanation:

Translation is moving a shape without rotating or resizing. So in this case it'll be 4.

8 0

3 years ago

Apply Laws of Exponents to write an equivalent expression.<br> (3y)-4. (2z)-4

Stels [109]

After Applying Laws of Exponents we can write as $(6yz)^{-4}$

<h3>What is law of exponents ?</h3>

The exponent of a number indicates how many times a number has been multiplied by itself. For instance, 34 indicates that we have multiplied 3 four times. Its full form is 3 3 3 3. Exponent is another name for a number's power. A whole number, fraction, negative number, or decimal are all acceptable.

<h3>How are powers of powers multiplied?</h3>

Exponents with distinct bases and the same powers can be multiplied by multiplying the bases and writing the power outside of the brackets.

$a^{n}$ . $b^{n}$ = $(a.b)^{n}$