Answer:
the answer sdhould be the third one
Answer/Step-by-step explanation:
How many total fish is Dr. Howser planning on buying?
BOTH tanks hold 120 gallons
Tank A :
3 every 10 --> 120/10 ---> 12
So multiply 3 and 12 ----> 36
36 fishes in tank A
Tank B:
6 every 40 -----> 120/40 ----> 3
So multiply 6 by 3 ----> 18
18 fishes are held in tank B
Add them together:
18 + 36 ----> 54
ANSWER : Dr. Howser is planing on purchesing 54 fish all together.
What will be the ratio of the number of small fish he buys to the number of large fish that he buys
Small ---> 36 fish
Large ---> 18 fish
Small : Large ----> 36:18
ANSWER: 36:18
if you need it siplified it would be 2:1
Answer:
(r-7)(r+2)
Step-by-step explanation:
First, let's look at the -14. Possible factors for that number are (-2, 7) (2, -7) (1, -14) and (-1, 14).
Now, let's look at the -5. How can we make -5 with the pairs that we just found?
The only possible way is 2 and -7 (added together equals -5)
First, let's establish a ratio between these two values. We'll use that as a starting point. I personally find it easiest to work with ratios as fractions, so we'll set that up:

To find the distance <em>per year</em>, we'll need to find the <em>unit rate</em> of this ratio in terms of years. The word <em>unit</em> refers to the number 1 (coming from the Latin root <em>uni-</em> ); a <em>unit rate</em> involves bringing the number we're interested in down to 1 while preserving the ratio. Since we're looking for the distance the fault line moves every one year, we'll have to bring that 175 down to one, which we can do by dividing it by 175. To preserve our ratio, we also have to divide the top by 175:

We have our answer: approximately
0.14 cm or
1.4 mm per year