Given:
<span>A: 3x + y = 6
</span><span>B: 6x - 2y = 4
</span><span>C: y = 3x - 2
</span><span>D: y = 1/3 x + 7
To figure out which two lines are perpendicular, we must look at the slopes of each one after putting them into standard form, y = mx + b.
Standard Form:
A: y = -3x + 6
B: y = 3x - 2
C: y = 3x - 2
D: y = (1/3)x + 7
Lines are perpendicular when their slopes are opposite inverses of eachother.
The opposite of -3 is 3 and the inverse of 3 is 1/3.
Therefore, lines A and D are perpendicular to one another :)
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Here’s the answer hope it helps: x≤−18
−3=8x−4y
,Step 1: Flip the equation.
,8x−4y=−3
,Step 2: Add -8x to both sides.
,8x−4y+−8x=−3+−8x
,−4y=−8x−3
,Step 3: Divide both sides by -4.
,−4y/−4
,=−8x−3/−4
,Answer:
y=2x+3/4
The answer would be ~30~ because 2*2^3 = 2^4= 16 then 3*6=18 then 16+18-4=30
Hope this helps
Have a great day/night
Feel free to ask any questions
