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andrew-mc [135]
2 years ago
10

while in Tokyo, Callie spent 547,000 Japanese yen for a strand of pearls. The cost of the pearls was equivalent to $5,000 in U.S

. currency. At the time of Callie's purchase, how many yen were equivalent to $20 in U.S. currency?
Mathematics
1 answer:
mamaluj [8]2 years ago
5 0

Answer:

2071.73 yen is equivelent to $20 in U.S Currency.

Step-by-step explanation:

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Strontium-90 has a half-life of 28.8 years. If you start with a 300-gram sample of strontium-90,
Kazeer [188]

Answer:  2.66 × 10⁻¹³

<u>Step-by-step explanation:</u>

First, use the decay formula   A=A_oe^{kt}   where

  • A is the final amount (amount left)
  • A₀ is the initial amount (amount you started with)
  • k is the rate of decay (you need to solve for this)
  • t is the time

Given:

  • A = 1/2(300) = 150
  • A₀ = 300
  • k = unknown
  • t = 28.8

150=300e^{28.8k}\\\\0.5=e^{28.8k}\\\\ln(0.5)=ln(e^{28.8k})\\\\ln(0.5)=28.8k\\\\\\\dfrac{ln(0.5)}{28.8}=k\\\\\\\large\boxed{-0.0240676=k}\\

Next, input the k-value and the new t-value to solve for A.

  • A = unknown
  • A₀ = 300
  • k = -0.0240676
  • t = 1440

A=300e^{1440(-.0240676)}\\\\\large\boxed{A=2.66\times 10^{-13}}\\

5 0
3 years ago
An important factor in selling a residential property is the number of times real estate, agents show a home. A sample of 21 hom
Natalka [10]

Using the t-distribution to build the 99% confidence interval, it is found that:

  • The margin of error is of 3.64.
  • The 99% confidence interval for the population mean is (19.36, 26.64).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 21 - 1 = 20 df, is t = 2.086.

The other parameters are given as follows:

\overline{x} = 23, s = 8, n = 21

The margin of error is given by:

M = t\frac{s}{\sqrt{n}} = 2.086\frac{8}{\sqrt{21}} = 3.64

Hence the bounds of the interval are:

\overline{x} - M = 23 - 3.64 = 19.36

\overline{x} + M = 23 + 3.64 = 26.64

The 99% confidence interval for the population mean is (19.36, 26.64).

More can be learned about the t-distribution at brainly.com/question/16162795

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