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maxonik [38]
2 years ago
13

I need help answering all of these

Mathematics
2 answers:
Mashcka [7]2 years ago
7 0

Answer:

A)-7

B)2

C)-2

D)-4

Step-by-step explanation:

kolezko [41]2 years ago
3 0

Answer:

well the (a) is -3 and (c) is 2

Step-by-step explanation:

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urgente ordenar de mas grande a mas pequeño estos numeros: 85,94 85,490 , 85,93, 85,035 ,85
Ilia_Sergeevich [38]
Largest to Smallest:- 

First lets write all the numbers down. 45, 94, 85, 490, 85, 93, 85, 035, 85. 

035 is 35. 

So lets order them now.

The biggest number is 490 and smallest is 35 (035).

490 - 94 - 93 - 85 - 85 - 85 - 85 - 035 (35)

4 0
3 years ago
Read 2 more answers
What’s the correct answer for this question?
scoray [572]

Answer: choice D 1/2

Step-by-step explanation:

Events A and B are independent if the equation P(A∩B) = P(A) · P(B) holds true.

so

1/6=1/3*p(A)

p(A)=1/2

4 0
3 years ago
There are 970 students in bayton high school. Brian takes a random sample of 100 students. He asks these 100 students which subj
Pani-rosa [81]

Answer:

How to do the estimation

Step-by-step explanation:

He can use the probability of how many people chose English and multiply by 9.7 since there are 970 people / 100 people who asked = 9.7

7 0
3 years ago
A jetliner goes from rest to a takeoff speed of 173 mi/h in 39.0 s. what is the magnitude of its average acceleration
Oliga [24]
Average acceleration = (173-0)/39=4.44m/s^2
3 0
3 years ago
The new ointment was applied to four locations, and a control was applied to the other four. How many different choices were the
lubasha [3.4K]

Answer:

there are 70 possible choices for the four locations to apply the new ointment

Step-by-step explanation:

Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) ,  each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant  , then we know that the number of choices is given by the number of combinations of 4 elements in 8

number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)

therefore

number of combinations = 8*7*6*5/(4*3*2*1 ) = 8!/((8-4)!*4!) = 70 possible combinations

thus there are 70 possible choices for the four locations to apply the new ointment

6 0
3 years ago
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