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allsm [11]
3 years ago
13

Quadrilateral ABCD ​ is inscribed in this circle.

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0
The sum of all interior angles in a polygon is

180(n-2), where n = sides, well, this is a QUADrilateral, so it has 4 sides, so the total is 360°.

now, let's find what angle C is first,

\bf \stackrel{A}{(2x-40)}+\stackrel{B}{(116)}+C+\stackrel{D}{(x)}=360\implies C+3x+76=360
\\\\\\
C+3x=284\implies C=284-3x

now, recall the "inscribed quadrilateral conjecture", where opposite angles are "supplementary angles", thus

\bf \stackrel{\measuredangle A}{(2x-40)}+\stackrel{\measuredangle C}{(284-3x)}=180\implies -x+244=180
\\\\\\
64=x\\\\
-------------------------------\\\\
\measuredangle A=2(64)-40
victus00 [196]3 years ago
6 0

The answer should be 88

Hope this helps and have good day


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