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allsm [11]
3 years ago
13

Quadrilateral ABCD ​ is inscribed in this circle.

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0
The sum of all interior angles in a polygon is

180(n-2), where n = sides, well, this is a QUADrilateral, so it has 4 sides, so the total is 360°.

now, let's find what angle C is first,

\bf \stackrel{A}{(2x-40)}+\stackrel{B}{(116)}+C+\stackrel{D}{(x)}=360\implies C+3x+76=360
\\\\\\
C+3x=284\implies C=284-3x

now, recall the "inscribed quadrilateral conjecture", where opposite angles are "supplementary angles", thus

\bf \stackrel{\measuredangle A}{(2x-40)}+\stackrel{\measuredangle C}{(284-3x)}=180\implies -x+244=180
\\\\\\
64=x\\\\
-------------------------------\\\\
\measuredangle A=2(64)-40
victus00 [196]3 years ago
6 0

The answer should be 88

Hope this helps and have good day


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At midnight, the temperature was -8° F. At noon, the temperature was 23° F. Which expression represents the increase in temperat
Mariana [72]

Answer:

C

Step-by-step explanation:

Increase is difference between ending and begining value so 23-(-8) =23+8.

In this case its absolute value because it has to be positive

6 0
3 years ago
These box plots show daily low temperatures for a sample of days in two
9966 [12]

Answer:

<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>

<u>IQR for town B, 10.</u>

Step-by-step explanation:

IQR = Q₃ - Q₁

For the town A:

Q₃ = 40  and Q₁ = 20

IQR of town A = 40 - 20 = 20

For the town B:

Q₃ = 30   and Q₁ = 20

IQR of town A = 30 - 20 = 10

Check the given options:

The most statement is appropriate comparison of the spreads is B

<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>

<u>IQR for town B, 10.</u>

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3 years ago
What is the solution to the equation 3(y-2)=2y-8 A.-2/5 B.-14 C. -2 D. -2 4/5 I NEED-HELP PLeAse
AlladinOne [14]

3(y - 2) = 2y - 8

3y - 6 = 2y - 8

3y - 2y = -8 + 6

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Answer: C

4 0
3 years ago
The percentage of cotton in material used to manufacture men's shirts follows.
velikii [3]

Answer:

Median = 34.55

Quartiles:

Q1 = 33.1

Q2 = 34.55

Q3 = 35.6

Inter Quartile range = 2.5

Step-by-step explanation:

Step 1

We arrange the given the following data from lowest to the highest

32.0, 32.1, 32.1, 32.2, 32.4, 32.5, 32.5, 32.5, 32.8, 32.8, 32.8, 32.8, 32.9, 32.9, 33.0, 33.0, 33.2, 33.2, 33.2, 33.2, 33.5, 33.6, 33.8, 33.8, 33.9, 34.0, 34.0, 34.1, 34.1, 34.3, 34.4, 34.5, 34.6, 34.6, 34.6, 34.7, 34.7, 35.0, 35.0, 35.1, 35.1, 35.2, 35.4, 35.5, 35.5, 35.5, 35.5, 35.6, 35.6, 36.1, 36.3, 36.4, 36.4, 36.4, 36.5, 36.6, 36.7, 36.7, 37.0, 37.1, 37.4, 37.4, 37.6, 37.8

a. Construct a stem-and-leaf display for the data.

Stem and leaf Display

Stem | Leaf

32 | 0,1,1,2,4,5,5,5,8,8,8,8,9,9

33 | 0,0,2,2,2,2,5,6,8,8,9

34 | 0,0,1,1,3,4,5,6,6,6,7,7

35 | 0,0,1,1,2,4,5,5,5,5,6,6,

36 | 1,3,4,4,4,5,6,7,7,

37 | 0,1,4,4,6,8

b. Calculate the median and quartiles of these data.

Number of terms = 64

1) Median = 1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

2) First Quartile

1/4(n + 1)th value

n = 64

= 1/4(64 + 1)th

= 1/4(65)th

= 16.5th value

This means it is between the 16th and 17th value

16th value = 33.0

17tj value = 33.2

= 33.0 + 33.2/2

= 66.2/2

= 34.55

Q1 --> 33.1

3)Second Quartile = Median

1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

Q2 --> 34.55

Third Quartile

3/4(n + 1)th value

n = 64

= 3/4(64 + 1)th

= 3/4(65)th

= 48.75 th value

This means it is towards the 49th value

32nd = 34.5

Hence,

Q3 --> 35.6

Inter Quartile range

Q3 - Q1

= 35.6 - 33.1

= 2.5

8 0
3 years ago
A number y multiplied by −3 is less than −2/5. Write this word sentence as an inequality.
bazaltina [42]
The answer is -3y < -2/5
8 0
3 years ago
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