Answer:
F = 120 N
Step-by-step explanation:
Given that,
The mass of the object, m = 20 kg
Acceleration of the object, a = 6 m/s²
We need to find the force exerted on an object. The force exerted on an object is given by :
So, the required force exerted on the object is 120 N.
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Answer:
Answer:
Option (b) is correct.
4x + 6y < 120 inequalities that can be paired with x + y ≥ 20 to create a system that represents the given situation.
Step-by-step explanation:
Given: A small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing. The dyers have to make at least 20 rugs, and they must do it in less than 120 hours.
We have write an inequalities that can be paired with x + y ≥ 20 to create a system that represents the given situation and choose the correct option from given options.
Let x represents the small rugs and y represents the medium rugs.
Also, x + y ≥ 20 represents the dyers have to make at least 20 rugs.
And it is given that a small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing and that they must do it in less than 120 hours.
So, time taken to dye x small rugs = 4x
also, time taken to dye y medium rugs = 6y
And they have maximum of 120 hours.
So this inequality is represented by 4x + 6y < 120
The answer is: 4x + 6y < 120
Answer:
Given that Angelo spends the same amount every day from the amount in
the lunch card, the function of the amount remaining is a linear function.
The constant rate of change of the function is; -5.25
The two ordered pairs used to find the constant rate of change are; (1, 44.75) and (2, 39.5)
Reasons:
The amount Angelo's mother put on the lunch card = $50
A possible table of values to the question is presented as follows;
Required:
The constant rate of the function that gives the amount remaining from the
amount Angelo's mother put on his lunch card.
Solution:
The two ordered pairs that can be used to find the slope or constant rate of change are;
(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)
With the above two ordered pairs, we have the constant rate of change of the function given as follows;
The constant rate of change for the function that gives the amount remaining in the lunch card is; -5.25
