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Mrac [35]
3 years ago
9

What is the value of (24-3) -44 -413 1-28

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

-4182

Step-by-step explanation:

(24-3)-44-4131-28               subtract the numbers in  (  ) first

21-44-4131-28                      calculate the difference ( subtract in order now)

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What is the range of the function on the graph?
STALIN [3.7K]

Answer:

the answer is D. all real numbers greater than or equal to 2.

Step-by-step explanation:

looking at the graph, half of a parabola is curved upwards, and will never stop going up. looking at (1, 2), the dot (instead of circle) indicates the range is greater than or equal to itself, which is 2.

8 0
3 years ago
Read 2 more answers
The image below shows two parallel lines cut by a transversal. What is the value of A
rewona [7]

<u>Answer</u>

59°


<u>Explanation</u>

There are 2 parallel line and one transverse.

Angles in a straight line add up to 180°

∴ 180 - (2a + 3) = 180 - 2a -3

                        = 177 - 2a

The angle (177 - 2a) corresponds to angle a in the diagram. The two corresponding angles are equal.

∴ 177 - 2a = a

  177 = a + 2a

3a  = 177

a = 177/3

  = 59°

3 0
3 years ago
How do you solve for range of exponential function?​
FromTheMoon [43]
For any exponential function, f(x) = abx, the range is the set of real numbers above or below the horizontal asymptote, y = d, but does not include d, the value of the asymptote.

Overall, the steps for algebraically finding the range of a function are:
Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).
Find the domain of g(y), and this will be the range of f(x).
If you can't seem to solve for x, then try graphing the function to find the range.
7 0
3 years ago
A rectangle with a width of 9 ft. and a length of 13 ft. is the base of a 30 ft. tall pyramid. What
natta225 [31]
3,510



913=117
11730=3,510

3,510
3 0
3 years ago
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
3 years ago
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