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Margaret [11]
4 years ago
13

Need help & Thank you !!!!

Mathematics
1 answer:
loris [4]4 years ago
8 0

The right answer is of option D.

please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment......

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An economist is studying the job market in Denver area neighborhoods. Let x represent the total number of jobs in a given neighb
lbvjy [14]

Answer:

a) \sum X = 13+34+52+28+50+25 =202

\sum Y = 1+4+5+5+9+3= 27

\sum X^2 = 13^2+34^2+52^2+28^2+50^2+25^2 = 1074

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

r=\frac{6(1074)-(202)(27)}{\sqrt{[6(7938) -(202)^2][6(157) -(202)^2]}}=0.821  

b) m=\frac{165}{1137.33}=0.145  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{202}{6}=33.67  

\bar y= \frac{\sum y_i}{n}=\frac{27}{6}=4.5  

And we can find the intercept using this:  

b=\bar y -m \bar x=4.5-(0.145*33.67)=-0.384  

So the line would be given by:  

y=0.145 x -0.384  

c) The coefficient of variation is given by:

r^2 = 0.821^2 = 0.674

And we can conclude that 67.4% of the variation in y can be explainedby the corresponding variation in x and the least-squares line

d) For this case we just need to replade x = 34 into our model and we got:

y=0.145*34 -0.384= 3.097  

Step-by-step explanation:

For this case we have the following data:

x 13 34 52 28 50 25

y 1 4 5 5 9 3

Part a

\sum X = 13+34+52+28+50+25 =202

\sum Y = 1+4+5+5+9+3= 27

\sum X^2 = 13^2+34^2+52^2+28^2+50^2+25^2 = 1074

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

r=\frac{6(1074)-(202)(27)}{\sqrt{[6(7938) -(202)^2][6(157) -(202)^2]}}=0.821  

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=7938-\frac{202^2}{6}=1137.33  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=1074-\frac{202*27}{6}=165  

And the slope would be:  

m=\frac{165}{1137.33}=0.145  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{202}{6}=33.67  

\bar y= \frac{\sum y_i}{n}=\frac{27}{6}=4.5  

And we can find the intercept using this:  

b=\bar y -m \bar x=4.5-(0.145*33.67)=-0.384  

So the line would be given by:  

y=0.145 x -0.384  

Part c

The coefficient of variation is given by:

r^2 = 0.821^2 = 0.674

And we can conclude that 67.4% of the variation in y can be explainedby the corresponding variation in x and the least-squares line

Part d

For this case we just need to replade x = 34 into our model and we got:

y=0.145*34 -0.384= 3.097  

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4 years ago
On a particular map, 3 inches on the map equates to 10 miles in real life. If you know that the real-life distance between two b
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Answer:

15\dfrac{39}{40} $ inches

Step-by-step explanation:

On the map, 3 inches = 10 miles in real life.

Therefore:

10 miles: 3 Inches

1$ miles rep $ \dfrac{3}{10}$ inches

If the real-life distance between two buildings is 53.25 miles

Distance on the map

\dfrac{3}{10}$ X 53.25 inches\\=15.975 inches

=15\dfrac{39}{40} $ inches

The distance between the two buildings on the map is therefore: 15\dfrac{39}{40} $ inches

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3 years ago
....................
4vir4ik [10]
Using the ratio 4/2 = 2
 and 8/4 = 2

 so they are similar because 4/2 equals 8/4

6 0
3 years ago
Can somebody please help me with the highlighted question?
Brrunno [24]
What does it say? half is cut off
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3 years ago
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