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Mice21 [21]
3 years ago
10

The function y=h(x) is defined as follows:

Mathematics
1 answer:
Lunna [17]3 years ago
7 0

Answer:

h(1) = 1

h(4) = 5

Step-by-step explanation:

Since 1 is in the interval 1 ≤ x ≤ 3, you must substitute 1 into the expression  x^{3}

So, h(1) = 1^{3} = 1

Since 4 is in the interval x > 3, and all values of x > 3 gives an output of 5, then h(4) = 5

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The midpoint of AB is M (2,0). If the coordinates of A are, (-3, 3), what are the coordinates of B?​
gregori [183]

Given:

M is the midpoint of AB.

M(2,0) and A(-3, 3).

To find:

The coordinates of point B.

Solution:

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Let the coordinates of point B are (a,b). Then, using the midpoint formula, we get

(2,0)=\left(\dfrac{-3+a}{2},\dfrac{3+b}{2}\right)

On comparing both sides, we get

\dfrac{-3+a}{2}=2

-3+a=2\times 2

a=4+3

a=7

And,

\dfrac{3+b}{2}=0

3+b=0

3+b-3=0-3

b=-3

Therefore, the coordinates of point B are (7,-3).

5 0
3 years ago
What’s the answer to this important problem it is very idk
White raven [17]
1) 4/(1/5)

=4 ÷ 1/5
to divide fractions, multiply by the reciprocal/inverse of 1/5

=4 * 5/1
=20


4) (7/9)/7

=7/9 ÷ 7
to divide fractions, multiply by the reciprocal/inverse of 7

=7/9 * 1/7
multiply numerators; multiply denominators

=(7*1)/(9*7)
=7/63
simplify by 7
=1/9


7) (9/10)/6

= 9/10 ÷ 6
to divide fractions, multiply by the reciprocal/inverse of 6

= 9/10 * 1/6
multiply numerators; multiply denominators

= (9*1)/(10*6)
= 9/60
simplify by 3
= 3/20


ANSWER: 1) 20; 4) 1/9; 7) 3/20

Hope this helps! :)
3 0
3 years ago
To classify a quadrilateral, use the slope of opposite sides to determine if the sides are ____________.
pogonyaev
Parallel or perpendicular
8 0
3 years ago
Simplify 2.1 + (-3.7m) + 1.9m - 1.4
belka [17]

Answer:

-1.8m + 0.7

Step-by-step explanation:

4 0
3 years ago
Ryker is given the graph of the function y= 1/2x^2 - 4 . He wants to find the zeros of the function but is unable to read them e
REY [17]
y = \frac{1}{2x^{2} - 4}
0 = \frac{1}{2x^{2} - 4}
0(2x^{2} - 4) = (2x - 4)(\frac{1}{2x^{2} - 4})
0(2x^{2}) - 0(4) = 1
0 - 0 = 1
0\neq1
8 0
3 years ago
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