What is the interquartile range of the following data set 2, 5, 9, 11, 18,30, 42, 55, 58, 73, 81
In-s [12.5K]
Answer:
4.2/5. 4.
Step-by-step explanation:
Answer:
Step-by-step explanation:
I = (P × R × T)/100
P = $72.80, R = 4 1/4 = 17/4, T = 2yrs
I = (72.8 × 17/4 × 2)/100
I = $6.19
Answer:
<h2>a) length x = 45ft</h2><h2>b) maximum area = 4050 ft²</h2>
Step-by-step explanation:
Given the quadratic equation A=−2x2+180x that gives the area A of the yard for the length x, to maximize the area of the yard then dA/dx must be equal to zero i.e dA/dx = 0
If A=−2x²+180x
dA/dx = -4x + 180 = 0
-4x + 180 = 0
Add 4x to both sides
-4x + 180 + 4x = 0 + 4x
180 = 4x
x = 180/4
x = 45
<em></em>
<em>Hence the length of the building that should border the yard to maximize the area is 45 ft</em>
<em></em>
To find the maximum area, we will substitute x = 45 into the modelled equation of the area i.e A=−2x²+180x
A = -2(45)²+180(45)
A = -2(2025)+8100
A = -4050 + 8100
A = 4050 ft²
<em>Hence the maximum area of the yard is equal to 4050 ft²</em>
Answer:
Jack: 4 x 6 = 24
Jill: 5.4 x 10 = 54
Step-by-step explanation:
Jack:
5 + 1 = 6
24 ÷ 6 = 4
4 = $4 per item
Jill:
6 + 4 = 10
54 ÷ 10 = 5.4
5.4 = $5.4
B: 11
N: 5
Hope this helps!
W <span>= </span><span>21 </span><span>cm</span>Hope that helped!