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avanturin [10]
2 years ago
9

There was a total of 184 teachers and students at an archery lesson.

Mathematics
1 answer:
Brums [2.3K]2 years ago
6 0
The question isn’t complete, doesn’t make sense. Can you rewrite the questions. Cuz I ain’t getting what the 2/5 or 3/4 referring to.
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Find the mean absolute deviation for the data set.<br> 5,6,6,8,10
alukav5142 [94]

Answer: 1.6

<u>Order the numbers</u>

5,6,6,8,10

<u>Add</u>

5+6+6+8+10=35

<u>Divide</u>

35÷5=7

Mean: 7

Sum divided by the count.

Final Answer: 1.6

6 0
3 years ago
Read 2 more answers
The ratio of boys to girls in Ella’s grade is 3 to 4. The ratio of boys to girls in Minh’s grade is 4 to 5. Each grade has a tot
Readme [11.4K]
(20:4)x3=15 (Ellas grade)
(20:5)x4=16 (Minhs grade)
5 0
2 years ago
Prove that the value of the expression<br> (16^3–8^3)(4^3 +2^3) is divisible by 63.
Darya [45]

Answer:

Step-by-step explanation:

16^3 - 8^3

Take out 8^3 as a common factor.

16^3 = 2^3 * 8^3

8^3(2^3 - 1)  

8^3(8 - 1) = 8^3 * 7

(4^3 + 2^3)     Expand

64 + 8            Combine

72

72 = 9 * 8

Conclusion

(8*3 * 7 )(9*8)

7*9 = 63

So any number containing 63 will divide into the reduced form of

(16^3–8^3)(4^3 +2^3)

7 0
2 years ago
a 15-foot telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 degre
scoundrel [369]

Answer:

The length of the wire is 22.42 feet

The distance from the base of the pole to the spot where the wire touches the ground is 16.66 feet

Step-by-step explanation:

* Lets explain the situation in the problem

- The telephone pole , the wire and the ground formed a right triangle

- The wire is the hypotenuse of the triangle

- The height of the telephone pole and the distance from the base of

 the pole to the spot where the wire touches the ground are the legs

 of the triangle

- The angle between the wire and the ground is 42°

- The angle 42° is opposite to the height of the telephone pole

- The height of the telephone pole is 15 feet

* Lets use the trigonometry functions to find the length of the wire

 (hypotenuse) and the distance from the base of the pole to the spot

 where the wire touches the ground

∵ sin Ф = opposite/hypotenuse

∵ Ф = 42° and its opposite side = 15 feet

∴ sin 42 = 15/hypotenuse ⇒ by using cross multiplication

∴ sin 42° (hypotenuse) = 15 ⇒ divide both sides by sin 42

∴ hypotenuse = 15/sin 42° = 22.42 feet

∵ The length of the wire is the hypotenuse

∴ The length of the wire is 22.42 feet

∵ The distance from the base of the pole to the spot where the wire

   touches the ground is the adjacent side to the angle 42°

∵ tan Ф = opposite/adjacent

∴ tan 42° = 15/adjacent ⇒ by using cross multiplication

∴ tan 42° (adjacent) = 15 ⇒ divide both sides by sin 42

∴ adjacent = 15/tan 42° = 16.66 feet

∵ The adjacent side is the distance from the base of the pole to the

  spot where the wire touches the ground

∴ The distance from the base of the pole to the spot where the wire

   touches the ground is 16.66 feet

7 0
3 years ago
A sprinter runs 400 meters in 54 seconds. What is the runner’s average running rate in meters per second? Round to the nearest t
Lyrx [107]

Answer:

Just divide

400/54=7.40

7.4 meters per second

hope this helps

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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