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3 years ago

1

Mathematics

1 answer:

Finger [1]3 years ago

8 0

Answer:

36 did not get an A on the test

Step-by-step explanation:

48/4*3=36

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Your answer should be a polynomial in standard form. (7h^3+8h) -(9h^3+h^2-2h)=(7h 3 +8h)−(9h 3 +h 2 −2h)

Snowcat [4.5K]

2h^3+h^2-8h=0 is in standard form

6 0

3 years ago

What is the value of x in the equation 3x-4y=65 when y =4

Dovator [93]

3x - 4(4) = 65

First, simplify 4 × 4 to get 16. / Your problem should look like: 3x - 16 = 65
Second, add 16 to both sides. / Your problem should look like: 3x = 65 + 16
Third, simplify 65 + 16 to 81. / Your problem should look like: 3x = 81
Fourth, divide both sides by 3. / Your problem should look like: x = $\frac{81}{3}$
Fifth, simplify $\frac{81}{3}$ to 27. / Your problem should look like: x = 27

Answer: x = 27

5 0

3 years ago

Can I have some help with some math does anyone know some math they could help me with

vovikov84 [41]

Answer:

It is an irrational number

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers

Question in the image

Komok [63]

Answer:

0.4

Step-by-step explanation:

consider this like some lines overlapping each other.

one line (A) is 0.5 long, the other (B) 0.4 long.

together they are 0.8 long.

that means that they overlap at a length of 0.1 (they share a segment 0.1 long).

of the combined line of 0.8 that has 0.1 of a joined segment, the complimentary part of B is therefore 0.4 (0.8 minus the original length of B).

8 0

3 years ago