Question

If ADEF = AJKL, DE = 18, EF = 23, DF = 9x - 23, JL = 7x-11, and JK = 3y - 21, find the

Answer 1

X=6 Y=13 values of x and y

Answer 2

Answer:

x = 6

y = 13

Step-by-step explanation:

since DE and JK are congruent, they are both 18

to find 'y':

3y - 21 = 18

3y = 39

y = 13

DF and JL are diagonals that are congruent so:

9x - 23 = 7x - 11

2x = 12

x = 6