If ADEF = AJKL, DE = 18, EF = 23, DF = 9x - 23, JL = 7x-11, and JK = 3y - 21, find the
2 answers:
X=6 Y=13 values of x and y
Answer:
x = 6
y = 13
Step-by-step explanation:
since DE and JK are congruent, they are both 18
to find 'y':
3y - 21 = 18
3y = 39
y = 13
DF and JL are diagonals that are congruent so:
9x - 23 = 7x - 11
2x = 12
x = 6
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