Answer:
Component Form: v = <-1,6>
Magnitude of v: ||v|| = √37
Direction of v: θv = 100° (to the nearest degree)
Step-by-step explanation:
Component Form: v = <(5-6),(3-(-3))> = <-1,6>
Magnitude of v: ||v|| = √[(-1)²+(6)²] = √(1+36) = √37
Direction of v: α = tan⁻¹|6/-1| = tan⁻¹|-6| = tan⁻¹(6) = 80.53° which is your reference angle, but to verify that the angle is in the second quadrant, you'll need to do θv = 180° - 80.53° = 99.47°, therefore your direction angle is θv=100° to the nearest degree.
Base case: if <em>n</em> = 1, then
1² - 1 = 0
which is even.
Induction hypothesis: assume the statement is true for <em>n</em> = <em>k</em>, namely that <em>k</em> ² - <em>k</em> is even. This means that <em>k</em> ² - <em>k</em> = 2<em>m</em> for some integer <em>m</em>.
Induction step: show that the assumption implies (<em>k</em> + 1)² - (<em>k</em> + 1) is also even. We have
(<em>k</em> + 1)² - (<em>k</em> + 1) = <em>k</em> ² + 2<em>k</em> + 1 - <em>k</em> - 1
… = (<em>k</em> ² - <em>k</em>) + 2<em>k</em>
… = 2<em>m</em> + 2<em>k</em>
… = 2 (<em>m</em> + <em>k</em>)
which is clearly even. QED
Answer: c. refraction
Step-by-step explanation:
W=-15 I hope this helped.
P=2(L+W)
if given one side and the perimiter
(P/2)-L=W
(P/2)-W=L
