Answer:
Roosting areas in buildings of any height are the resource partitioning of both bat species.
Explanation:
- The <em>fundamental niche</em> refers <u>only </u>to <u>physic conditions</u> in which a species can live and survive in the absence of any interaction with other species.
- The <em>realized niche</em> refers to the <u>restricted conditions</u> in which a species can live and survive as a result of <u>environment physic characteristics</u> and the <u>interaction</u> with other species.
- <em>Competitive exclusion</em> refers to the <u>exclusion</u> of the inferior competitor by the superior competitor when there is not habitat differentiation, and both species can not share the same niche. In this case, the effective niche of the dominant species completely occupies the fundamental niche of the inferior competitor.
- Resources partitioning refers to one dominant species monopolizing the resources, and the other inferior species use resources -partially or completely-, migrates or get extinguished.
A way in which species can divide resources is by living in different habitat areas. These species <em>might eat the same food</em>, and <em>can roost in different places</em> within the same habitat. This resource partitioning and differentiation in the function of their physic location allows both species to coexist more effectively.
In the present example, both bat species can coexist in the same city but the weaker bat species (species 1) roost at the top of the shorter buildings while dominant species (species 2) roost at the top of the highest buildings.
Answer:
????
Explanation:
None of those seem to be correct to me.
1. Observations are made using the five senses- sight, sound, touch, taste, and smell. So this is invalid.
2. Observations and experiments can both be done anywhere
3. See answer to 2
4. It's cut off? But observations can literally be as simple as looking at a stick and noting that it's brown, so from what I can read, it's invalid.
Answer:
1) In the first step, we need to predict the possible alleles for the cross. The dominant allele will be written with a capital letter. The recessive allele will be written with a small letter. Hence, the allele for brown hair colour will be B and the allele for red hair colour will be b.
2) In the second step, we need to determine the genotype of the parents. The genotype of the homozygous dominant parent will be BB. The genotype of the heterozygous brown hair colour will be Bb.
3) The punnet square for cross between these parents can be shown as follows:
B b
B BB Bb
B BB Bb
4) In the fourth step, lets determine the phenotype of the children. The phenotype of all the offsprings born will be brown hair colour.
5) The genotype from the punnet square shows that there is a 50% chance that the offsprings will be heterozygous dominant (Bb) for brown hair colour and their will be a 50% chance that the child born will be homozygous dominant (BB).
The answer is true because the weight of all of the parts is 2300 when you put them together they will stay 2,300