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3 years ago

Please help

Mathematics

1 answer:

KonstantinChe [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Sum of two sides of triangle always greater than third side, so the possible values of h is:

7x-3x < h < 7x+3x

4x < h < 10x

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Simplify the following leave the answer in radical notation:

Nataliya [291]

Answer:

1- 5xy³√5y

2- 2xy²∛3y²

Step-by-step explanation:

√125x²y^7=

√25*5x²y^6y

5xy³√5y

2) ∛24x³y^8=

∛2³*3x³y^8=

2xy²∛3y²

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3 years ago

Find the area of the right triangle

xenn [34]

Answer:

Area: 24 sq units

Step-by-step explanation:

Area of a rectangle formula:

A = 0.5bh

Given:

b = 6

h = 8

Work:

A = 0.5bh

A = 0.5(6)(8)

A = 3(8)

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2 years ago

Read 2 more answers

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

(2n-9)-(-2.4n+4) Please help!

Furkat [3]

Answer: =4.4n-13

Step-by-step explanation:

Let's simplify step-by-step.

2n−9−(−2.4n+4)

Distribute the Negative Sign:

=2n−9+−1(−2.4n+4)

=2n+−9+−1(−2.4n)+(−1)(4)

=2n+−9+2.4n+−4

Combine Like Terms:

=2n+−9+2.4n+−4

=(2n+2.4n)+(−9+−4)

=4.4n+−13

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3 years ago

The Petersons deposited $1,000 in an account that earns 2% annual simple interest. How many years will it take the amount in the

noname [10]

Yhjtjhjtgjtbnj vghjghjytgtgjnc njc tgyjtcgtc

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3 years ago