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3 years ago

How many eighty-fours are in 672?

Mathematics

2 answers:

Mandarinka [93]3 years ago

8 0

8 eighty-fours in 672

We figure this out by dividing 672 by 84.

Hope this helps! Good luck! :D

harina [27]3 years ago

3 0

Answer:

There are 8 eighty-fours in 672.

Step-by-step explanation:

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Garph x > 2. I need Help!!!!!!!!!

bija089 [108]

Answer:

where am i supposed to graph it?

you didnt attach a graph or anything but i will try to help

x>2= x needs to be greater than 2

For example:

3>2
6>2
4>2
20>2

Step-by-step explanation:

Hope this help

:))

4 0

3 years ago

Find the midpoint of the segment with endpoints of (1,-6) and (-3, 4) and

Zielflug [23.3K]

Answer:

Mid point = (–1 , –1)

Step-by-step explanation:

From the question given above, the following data were obtained:

(1, –6)

(–3, 4)

x₁ = 1

x₂ = –3

y₁ = –6

y₂ = 4

Mid point = (X, Y)

X = (x₁ + x₂)/2

X = (1 + –3)/2

X = (1 – 3)/2

X = –2/2

X = –1

Y = (y₁ + y₂)/2

Y = (–6 + 4)/2

Y = –2/2

Y = –1

Mid point = (X, Y)

Mid point = (–1 , –1)

8 0

4 years ago

Assume the heights in a female population are normally distributed with mean 65.7 inches and standard deviation 3.2 inches. Then

maria [59]

Answer:

Choice a. approximately $0.62$ .

Step-by-step explanation:

This explanation shows how to solve this problem using a typical $z$ -score table. Consider a normal distribution with mean $\mu$ and variance $\sigma^2$ . The $z\!$ -score for a measurement of value $x$ would be $(x - \mu) / \sigma$ .

Convert all heights to inches:

$5\; \rm ft = 5 \times 12 \; in = 60\; \rm in$ .
$5\; \rm ft + 7\; \rm in = 5 \times 12 \; in + 7\; \rm in = 67\; \rm in$ .

Let $X$ represent the height (in inches) of a female from this population. By the assumptions in this question: $X \sim \mathrm{N}(65.7,\, 3.2)$ . The question is asking for the probability $P(60 \le X \le 67)$ . Calculate the $z$ score for the two boundary values:

For the lower bound, $60\; \rm in$ : $\displaystyle z = \frac{60 - 65.7}{3.2} \approx -1.78$ .
For the upper bound, $67\; \rm in$ : $\displaystyle z = \frac{67 - 65.7}{3.2} \approx 0.41$ .

Look up the corresponding probabilities on a typical $z$ -score table.

For the $z$ -score of the upper bound, the corresponding probability is approximately $0.6591$ . In other words:

$P(x \le 67) \approx 0.6591$

On the other hand, some $z$ -score table might not include the probability for negative $z\!$ scores. That missing part can be found using the symmetry of the normal distribution PDF.

The probability corresponding to $P(z < 1.78)$ (that's the opposite of the $z\!$ -score at the lower bound) is approximately $0.9625$ . By the symmetry of the normal PDF:

$P(z < -1.78) = 1 - P(z < 0 - (-1.78)) \approx 1 - 0.9625 = 0.0375$ .

Therefore:

$P(X < 60) \approx 0.0375$ .

Calculate the probability of the interval between the two bounds:

$\begin{aligned}P(60 \le X \le 65.7) &= P(X \le 65.7) - P(X \le 60)\\ &\approx 0.6591 - 0.0375 \approx 0.62 \end{aligned}$ .

5 0

4 years ago

−4y−4+(−3)

bearhunter [10]

Hope this helps!!!:)))

5 0

3 years ago

Read 2 more answers

A merchant blends tea that sells for $3.25 an ounce with tea that sells for $2.50 an ounce to produce 90 oz of a mixture that se

Nookie1986 [14]

Answer: The amount of tea ounces that sells for $ 3.25 is 36, and the amount of tea ounces that sells for $ 2.50 is 54.

Step-by-step explanation:

We start by defining variables from the data provided:

a = amount of ounces of tea that sells for $ 3.25

b = amount of ounces of tea that sells for $ 2.50

c = amount of ounces of tea that sells for $ 2.80

From the problem we know that $a + b = c$ , and that $3.25 * a + 2.50 * b = 2.80 * c$ . You can propose a system of equations:

$\left \{ {{a + b = c} \atop {3.25 * a + 2.50 * b = 2.80 * c}} \right.$

Having the fact that c = 90, we can simplify the system:

$\left \{ {{a + b = 90} \atop {3.25 * a + 2.50 * b = 252}} \right.$

Clearing a in the first equation we get:

$a = 90 - b$

And substituting in the second equation we arrive at:

$3.95 * (90 - b) * 2.50 * b = 252, we\ apply\ the\ distributive\ property\\ 292.5 - 3.25 * b + 2.50 * b = 252, add\ the\ terms\ containing\ b\\292.5 - 0.75 * b = 252, we\ subtract\ 292.5\ from\ both\ sides\\- 0.75 * b = -40.5, we\ divide\ by -0.75\\b = 54$

Now we can use b in the first equation to get a:

$a = 90 - b = 90 - 54 = 36$

We verify that $36 + 54 = 90$ , and that $3.25 * 36 + 2.50 * 54 = 252$ .

7 0

4 years ago