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ArbitrLikvidat [17]
3 years ago
9

Garph x > 2. I need Help!!!!!!!!!

Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

where am i supposed to graph it?

you didnt attach a graph or anything but i will try to help

x>2= x needs to be greater than 2

For example:

  • 3>2
  • 6>2
  • 4>2
  • 20>2

Step-by-step explanation:

Hope this help

:))

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Please help, I will give brainliest, I am struggling badly.
Alja [10]

Answer:

Step-by-step explanation:

Notice they both have the same slope of 3x so they are parallel, but different y intercepts. This means the lines never intersect and thus there are no solutions to the system of equations.

3 0
2 years ago
Read 2 more answers
Pls help me, I really dont understand
Stella [2.4K]

Answer:

-2.5x-.5

y=\frac{2}{3}x-1

draw the dotted line (3/7)x-3 and shade below it

Step-by-step explanation:

First, we need the slope

Use the slope formula:

\frac{Y_2-Y_1}{X_2-x_1}=\frac{2-(-8)}{-1-3}=\frac{10}{-4}=-2.5

so we have

y= -2.5x+b

Solve for b by plugging in coordiantes

-8= -2.5(3)+b

-8= -7.5+b

b= -.5

Put it together and get -2.5x-.5

2.)

A line is parallel to another line if they have the same slope (and different y intercepts)

So in the formula y=mx+b we knowe that m= 2/3

Now it's just a matter of solving for B

plug in the required coordinate to do this

-1=(2/3)*0+b

-1= b

Put it all together to get

y=\frac{2}{3}x-1

3.)

put this into slope intercept form

3x-7y>21

3x-21 > 7y

(3/7)x-3 >y

To graph this just draw a dotted line with the equation (3/7)x-3 and shade everything below it (use de_smos if you're stuck)

7 0
3 years ago
Where does the normal line to the parabola y = x − x2 at the point (1, 0) intersect the parabola a second time?
Ksivusya [100]
Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)

we just need the slope

take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1

the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation

solve for where y=x-1 and y=x-x² intersect

set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero

x-1=0
x=1
we got this point already

x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2

it intersects at (-1,-2)
7 0
3 years ago
Help me plz I will give brainliest
Zarrin [17]

Answer:

Step-by-step explanation:

(35 - 20)/20

15/20 = .75

.75 * 100 == 75%

75%

6 0
3 years ago
Write an expression for four times the product of -9 and x and then simplify it.
katrin2010 [14]
4(-9*x)

Multiply the two numbers
-36x

Final answer: -36x
5 0
3 years ago
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