Answer:
yes
Step-by-step explanation:
Since there is a common difference of one, this is an arithmetic sequence of the form a(n)=a+d(n-1) which in this case is:
a(n)=15+1(n-1)
All arithmetic sequences have a sum which is equal to the average of the first and last terms time the number of terms, mathematically:
s(n)=(2an+dn^2-dn)/2 (that is just the result of ((a+a+d(n-1))(n/2)) )
Since a=15 and d=1 this becomes:
s(n)=(30n+n^2-n)/2
s(n)=(n^2+29n)/2 so
s(10)=(100+290)/2
s(10)=195 logs
Answer:
V≈155.76ft³
Step-by-step explanation:
V≈155.76ft³ nearest 10th will be 160 ft3
Answer:
I have a test on thursday toooooooo
Step-by-step explanation:
