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Lina20 [59]
3 years ago
5

A city has a population of 290,000 people. Suppose the population grows by 3%. What will the population be after 11 years?

Mathematics
2 answers:
White raven [17]3 years ago
8 0
.03(290,000) = 8700 ppl


8700 + 290,000= 298,700 ppl
LiRa [457]3 years ago
4 0
Assuming it grows 3% each year it would be <span>385,700</span>
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The cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20

<em><u>Solution:</u></em>

Let "a" be the cost of each ribeye steak dinners

Let "b" be the cost of each grilled salmon dinners

<em><u>A waitress sold 11 ribeye steak dinners and 12 grilled salmon​ dinners, totaling ​$560.63 on a particular day</u></em>

Thus we frame a equation as:

11 x cost of each ribeye steak dinners + 12 x cost of each grilled salmon dinners = 560.63

11 \times a + 12 \times b = 560.63

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<em><u>Another day she sold 16 ribeye steak dinners and 6 grilled salmon​ dinners, totaling ​$584.46</u></em>

Thus we frame a equation as:

16 x cost of each ribeye steak dinners + 6 x cost of each grilled salmon dinners = 584.46

16 \times a + 6 \times b = 584.46

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<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 2 by 2</u></em>

32a + 12b = 1168.92 ------- eqn 3

<em><u>Subtract eqn 1 from eqn 3</u></em>

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( - ) ----------------

21a = 1168.92 - 560.63

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Divide both sides by 21

a = 28.96 \approx 29

<em><u>Substitute a = 29 in eqn 1</u></em>

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12b = 560.63 - 319

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Divide both sides by 12

b = 20.13 \approx 20

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