Answer:go there and it will answer your question
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Step-by-step explanation:
Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
The probability of getting a 2 or a getting a black card, find individual probabilities;
A standard deck has 52 cards.
There are 4 2's in a normal deck; probability of getting it is 4/25
The probability of getting a black card is; 26/52 since half the deck is red and black.
Now add up the probabilities since it says "or"
(4/52)+(26/52)=30/52 probability of the card that you were dealt being a two or a black card.
Hope I helped :)
Answer:
The claim is rejected
Step-by-step explanation:
Claim: UCF is advertising their bachelor in Economics with the statistic that the starting salary of a graduate with a bachelor in economics is $ 48,500 according to Payscale (2013-13).
Null hypothesis: 
Alternate hypothesis :
n = 50
Since n is more than 30 .
So we will use Z test
x=43350
Standard deviation = 15000
Refer the z table
p value = 0.00776
p value < 
So, We are failed to accept null hypothesis
Hence The claim is rejected
Answer:
1: B
Step-by-step explanation:
