The equation, in point-slope form, of the line that is parallel to the given line and passes through the point is y - 1 = 3/2(x+3)
<h3>Equation of a line</h3>
A line is the distance between two points. The equation of a line in point-slope form is expressed as:
y - y0 = m(x-x0)
Given the coordinates (-2, -4) and (2, 2) on the line, the slope is expressed as:
Slope = 2-(-4)/2-(-2)
Slope = (6)/4
Slope = 3/2
Find the equation of the line
y -(1) = 3/2(x-(-3))
y - 1 = 3/2(x+3)
Hence the equation, in point-slope form, of the line that is parallel to the given line and passes through the point is y - 1 = 3/2(x+3)
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Answer:
c'( 7,-8) , T < -3 , -5 > 0r
180
Step-by-step explanation:
hope this helps
Answer:
Subtract 23 from both sides
Step-by-step explanation:
This is how algebra works, to get a variable by itself you have to do the opposite to both sides. Hope this helped.
Answer:
Addition POE
Step-by-step explanation:
I believe it is the addition POE because
12x-4=44
To get 4 (the constant) to the right you have to do the inverse of subtraction which is addition. By doing so You would add 4 to both side, canceling it out on the left side and adding the 4 to the right side (44).
12x-4=44
<u> +4 +4</u>
12x=48
12/12=48/12
x=4
6.0⋅<span>102</span><span>kg m<span>−3</span></span>
Explanation:
In order to find the density of the bowling ball, <span>ρ
</span>, you must determine the mass one unit of volume of this bowling ball would have.
Notice that the problem provides you with the volume of the bowling ball expressed cubic meters, <span><span>m3</span>
</span>, which means that one unit of volume would be <span><span>1 m3</span>
</span>.
Now, you know that a volume of <span><span>0.0050 m3</span>
</span> has a mass of <span>3.0 kg
</span>. You can use this known proportion as a conversion factor to figure the mass of <span><span>1 m3</span>
</span>
<span><span>1<span>m3</span>⋅<span>3.0 kg<span>0.0050<span>m3</span></span></span>=600 kg</span>
</span>
So, you know that one unit of volume has a mass of <span>600 kg
</span>, which means that the bowling ball's density is equal to
<span><span><span>ρ=6.0⋅<span>102</span><span>kg m<span>−3</span></span></span><span>−−−−−−−−−−−−−−−−−</span></span>
</span>
The answer is rounded to two sig figs.
