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2 years ago

Which shape has parallel lines and at least one acute angle

Mathematics

2 answers:

kkurt [141]2 years ago

6 0

Answer:

c = trapezoid

Step-by-step explanation:

The rest of the shapes have either right or obtuse angles.

galina1969 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

c is the only shape on here with acute angles, the top and bottom bases are parallel w/ each other

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The value of

marusya05 [52]

$\large\underline{\sf{Solution-}}$

We have to find out the value of the fraction.

Let us assume that:

$\sf \longmapsto x =2 + \dfrac{1}{2 + \dfrac{1}{2 + \dfrac{1}{2 + ... \infty} } }$

We can also write it as:

$\sf \longmapsto x =2 + \dfrac{1}{x}$

$\sf \longmapsto x =\dfrac{2x + 1}{x}$

$\sf \longmapsto {x}^{2} =2x + 1$

$\sf \longmapsto {x}^{2} - 2x - 1 = 0$

Comparing the given equation with ax² + bx + c = 0, we get:

$\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b = - 2 \\ \sf c = - 1 \end{cases}$

By quadratic formula:

$\sf \longmapsto x = \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

$\sf \longmapsto x = \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}$

$\sf \longmapsto x = \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}$

$\sf \longmapsto x = \dfrac{2 \pm \sqrt{8} }{2}$

$\sf \longmapsto x = \dfrac{2 \pm2 \sqrt{2} }{2}$

$\sf \longmapsto x = 1 \pm\sqrt{2}$

$\sf \longmapsto x = \begin{cases} \sf 1 + \sqrt{2} \\ \sf 1 - \sqrt{2} \end{cases}$

But "x" cannot be negative. Therefore:

$\sf :\implies x = 1 + \sqrt{2}$

So, the value of the fraction is 1 + √2.

4 0

2 years ago

Evaluate: (d + 1)(d - 1 + 6) d = 2

Allisa [31]

F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21

3 0

2 years ago

I will upvote and give brainliest answer

zloy xaker [14]

Answer:

x=17

Step-by-step explanation

i just did the exact same question on a test and got it right .

6 0

2 years ago

Give two examples of line segments that will make a triangle ?

77julia77 [94]

Answer:

If the length of any one side is greater than the sum of the length of the other two, the line segments cannot be used to create a triangle. It is possible to create a triangle using 3 line segments if the sum of the lengths of any two line segments is greater than the length of the third.

7 0

2 years ago

I have 45 cents in nickels.

pentagon [3]

Answer:

135

Step-by-step explanation:

43 times 3 is 135

5 0

2 years ago