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Sphinxa [80]
3 years ago
6

In the diagram below, is circumscribed about quadrilateral ABCD . What is the value of ?

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

C

Step-by-step explanation:

There's a property of cyclis quadrilaterals that say that opposite sides will add up to 180

so we have

5x+75=180\\\\5x=180-75\\\\5x=105\\\\x=21

which is option c

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Answer: A. approximately 37.33° above the ground

Step-by-step explanation:

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A six foot man is standing 10 feet away from a 20 foot lamppost. what is the length of his shadow?
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There are two congruent triangles that are being formed from the lamppost, the light, the ground and the man. Always try to draw a picture for these types of problems. It helps a lot when solving. Your answer should be about 4.3ft

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A parking lot is 20 feet long. One tortoise starts at the edge of the parking lot and moves at a rate of 6 feet per minute. Anot
anygoal [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Length of parking lot = 20 feets

Speed of tortoise which starts at the edge = 6 feets per minute

Speed of tortoise which starts 4 feets from the edge = 2 feets per minute

Equation to represent when they will be in the same spot.

Distance = speed * time

Distance of Tortoise at edge = 6ft/min * t = 6t - - (1)

Distance of the other tortoise = (4 + 2t) - - - (2)

Equating both (1) and (2)

6t = 4 + 2t

6t - 2t = 4

4t = 4

t = 4/4

t = 1

Hence, they'll be at the same spot after 1 minute.

6 0
3 years ago
A tile installer plots an irregular shape on grid paper. Each square on the grid represents 1 square
N76 [4]

Answer:

area of a triangle = 0.5 X base X height

0.5 X 4 X 4 = 8 cm^

area of a rectangle l X w

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area of a parallelogram = base X height

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add totals together

15 + 15 + 8 = 38 cm^

8 0
3 years ago
A ball is thrown straight up with a initial velocity of 56 feet per second . The height , h , of the ball t seconds after it is
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<span>Formula: H(t) = 56t – 16t^2   </span>

H(t) = - 16t^2 + 56t

<span><span>A.      </span>What is the height of the ball after 1 second? H (1) = 56(1) – 16(1) ^2 = 40 pt.</span>

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<span><span>C.      </span><span>After how many seconds will it return to the ground? – 16t^2 + 56t = 0   - 8t =0 t = 0</span></span>

<span><span>-          </span><span>8t (2 + - 7) = 0     2t – 7 = 0  t = 7/2   Ans: 3.5 seconds</span></span>

3 0
4 years ago
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