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Sphinxa [80]
3 years ago
6

In the diagram below, is circumscribed about quadrilateral ABCD . What is the value of ?

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

C

Step-by-step explanation:

There's a property of cyclis quadrilaterals that say that opposite sides will add up to 180

so we have

5x+75=180\\\\5x=180-75\\\\5x=105\\\\x=21

which is option c

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Plotting Equivalent Ratios
m_a_m_a [10]
Mr. Hendricks is plotting equivalent ratios
on a coordinate plane. One of the ordered
pairs is (3,5) Which other ordered pair
could he plot? O (4, 6) O (6,4) 0 (6, 10) 0
(10, 6)
3 0
2 years ago
Read 2 more answers
A square has sides of length 8.4 . Work out the length of a diagnol of the square . Give your answer correct to 3 significant fi
sweet [91]

Answer:

The length of the diagonal is 11.879 units

Step-by-step explanation:

On any rectangle or square, any 2 adjacent sides and the diagonal that connects them makes a right triangle. The diagonal is the hypotenuse of that right triangle, and you can find it using the pythagorean theorem:

a^2+b^2=c^2

where a and b are the sides, and c is the diagonal.

\rightarrow8.4^2+8.4^2=c^2\\\rightarrow70.56+70.56=c^2\\\rightarrow c^2=141.12\\\rightarrow c\approx11.879

3 0
3 years ago
Help pls with answer!!!Rewrite the function in the given form.
Elis [28]

Answer:

g(x) = \frac{-2}{x-1}+5\\\\

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

g(x) = \frac{5x-7}{x-1}\\\\g(x) = \frac{5x-5-2}{x-1}\\\\g(x) = \frac{(5x-5)-2}{x-1}\\\\g(x) = \frac{5(x-1)-2}{x-1}\\\\g(x) = \frac{5(x-1)}{x-1}+\frac{-2}{x-1}\\\\g(x) = 5+\frac{-2}{x-1}\\\\g(x) = \frac{-2}{x-1}+5

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation g(x) = \frac{-2}{x-1}+5\\\\ to the form g(x) = \frac{a}{x-h}+k\\\\

We can see that

  • a = -2
  • h = 1
  • k = 5

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

  • (-1,6)
  • (0,7) .... y intercept
  • (1.4, 0) .... x intercept
  • (2, 3)
  • (3, 4)

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.

7 0
3 years ago
The football team lost 4 yards on 2 plays in a row. Which of the following could represent the change in field position?
Over [174]
Lost (⬅key word) 4 is equal to -4
On 2 plays that is times 2
So all together is -4×2
A negative times a positive is negative
-4×2= -8
Hope this helped you☺
8 0
3 years ago
Nine less than a number is no more than 8 and is no less than 3
frozen [14]

9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1

9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6

So the number is between 1 and 6, notation 1 < x < 6

7 0
4 years ago
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