Question

A jogger ran 3 miles due east of his house. then he ran 5 miles at a heading of 30o east of north (or 30o ne). how far is he from his house after running 8 miles

Answer 1

Answer:

Distance of the jogger from his house is 7 miles.

Step-by-step explanation:

We are given that,

Distance ran towards east = 3 miles

Distance ran towards east of north = 5 miles

Angle made towards east of north = 30° as shown in the figure below.

So, the total angle by which the jogger ran = 90° + 30° = 120°

Thus, using the cosine law, we get,

$x^{2}=3^2+5^2-2\times 3\times 5\times \cos 120$

i.e. $x^{2}=9+25-30\times -0.5$

i.e. $x^{2}=34+15$

i.e. $x^{2}=49$

i.e. x = ±7 miles

Since, the distance cannot be negative.

Thus, the distance of the jogger from his house is 7 miles.

Answer 2

Is that meant to 30 degrees or what are the units for east or north maybe its a trick questions? im probably over thinking it, ill just say its 8 miles from his house