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julia-pushkina [17]
2 years ago
10

HELPPP ASAP WILL MARK BRAINLEST!!!!!!

Mathematics
1 answer:
Ulleksa [173]2 years ago
8 0

Answer:Can’t see what the stuff says

Step-by-step explanation:

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If f(x) = 5x2 − 2x, 0 ≤ x ≤ 3, evaluate the Riemann sum with n = 6, taking the sample points to be right endpoints. R6 =
Leona [35]

Answer:

46.375

Step-by-step explanation:

Given information:

f(x)=5x^2-2x

where, 0 ≤ x ≤ 3.

We need to divde the interval [0,3] in 6 equal parts.

The length of each sub interval is

\dfrac{b-a}{n}=\dfrac{3-0}{6}=0.5

Right end points are 0.5, 1, 1.5, 2, 2.5, 3.

The value function on each right end point are

f(0.5)=5(0.5)^2-2(0.5)=0.25

f(1)=5(1)^2-2(1)=3

f(1.5)=5(1.5)^2-2(1.5)=8.25

f(2)=5(2)^2-2(2)=16

f(2.5)=5(2.5)^2-2(2.5)=26.25

f(3)=5(3)^2-2(3)=39

Riemann sum:

\sum_{n=1}^6 f(x_n)\Delta x_n

Sum=[f(0.5)+f(1)+f(1.5)+f(2)+f(2.5)+f(3)]\times 0.5

Sum=[0.25+3+8.25+16+26.25+39]\times 0.5

Sum=92.75\times 0.5

Sum=46.375

Therefore, the Riemann sum with n = 6 is 46.375.

6 0
2 years ago
100 point for free giving it away bc I want to be nice
vodka [1.7K]

Answer:

i'll take. thank you

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
How do I write 3/4 and 1/6 as a complex fraction PLEASE HELP ITS DUE IN 12 mins!!
djverab [1.8K]

Answer:

3/4 as a complex fraction is -1^7/8(fraction form)  and 1/6 as a complex fraction is -5/12 as a fraction

Step-by-step explanation:

6 0
2 years ago
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2x+6y=-24 converted into a slope intercept?
Svetllana [295]

Answer:

y=1/3x+4

Step-by-step explanation:

6 0
3 years ago
The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr
Kobotan [32]

Answer:

%  change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

T = 2.5 x + 0.5 x^{2}

We will approximate this distance  using the relation

f (x + dx) = f (x)+ f' (x)dx

dx = 26 - 25 = 1

T' =  2.5 + x

Therefore

f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× 25^{2} + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × 25^{2}

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

%  change in stopping distance = \frac{27.5}{375} × 100

%  change in stopping distance = 7.34 %

6 0
3 years ago
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